/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q.15 What is free-fall acceleration t... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

What is free-fall acceleration toward the sun at the distance of the earth’s orbit? Astronomical data are inside the back cover of the book .

Short Answer

Expert verified

Acceleration of free fall towards the sun at the distance of earth's orbit is 5.9×10-3m/s2.

Step by step solution

01

Given information 

Given in the question that, Astronomic data in the book,

02

Explanation

WE know, F=GMsunmR2

Again, F=mgsun

So

mgsun=GMsunmR2

gsun=MsunGR2

03

Acceleration of free fall

Here,

Msun=1.99×2030kg

localid="1649396961498" G=6.67×10−11Nm2/kg2

And R=Rsun-earth-Rearth

localid="1649396020677" =1.5×1011m-6.4×106m

localid="1649395379454" =1.499936×1011m

localid="1649395636670" gsun=1.99×1030kg×6.67×10−11Nm2/kg21.499936×1011m2

=5.9×10−3m/s2

04

Final answer

Acceleration of free fall towards the sun at the distance of earth's orbit is 5.9×10-3m/s2.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Space scientists have a large test chamber from which all the air can be evacuated and in which they can create a horizontal uniform electric field. The electric field exerts a constant horizontal force on a charged object. A 15gcharged projectile is launched with a speed of 6.0m/s at an angle35° above the horizontal. It lands 2.9m in front of the launcher. What is the magnitude of the electric force on the projectile?

A 500g model rocket is on a cart that is rolling to the right at a speed of 3.0m/s. The rocket engine, when it is fired, exerts an8.0N vertical thrust on the rocket. Your goal is to have the rocket pass through a small horizontal hoop that is 20m above the ground. At what horizontal distance left of the hoop should you launch?

Mass m1on the frictionless table of FIGURE EX8.13 is connected by a string through a hole in the table to a hanging mass m2. With what speed must m1 rotate in a circle of radius rif m2is to remain hanging at rest?

FIGURE EX8.13

You can swing a ball on a string in a vertical circle if you swing it fast enough. But if you swing too slowly, the string goes slack as the ball nears the top. Explain why there’s a minimum speed to keep the ball moving in a circle.

conical pendulum is formed by attaching a ball of mass m to a string of length L, then allowing the ball to move in a horizontal circle of radius r. FIGURE P8.47 shows that the string traces out the surface of a cone, hence the name.
a. Find an expression for the tension T in the string.
b. Find an expression for the ball’s angular speed v.
c. What are the tension and angular speed (in rpm) for a 500 g ball swinging in a 20-cm-radius circle at the end of a 1.0-m-long string?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.