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A 9.4×1021kgmoon orbits a distant planet in a circular orbit of radius 1.5×108m. It experiences a 1.1×1019Ngravitational pull from the planet. What is the moon’s orbital period in earth days?

Short Answer

Expert verified

The moon's orbital period in earth days is =26days

Step by step solution

01

Given information 

Moon orbit's mass =9.4×1021kg

Moon orbit's radius=1.5×108m

Gravitational pull=1.1×1019N

02

Explanation

Gravitational pull =F=GMmr2

localid="1649397302533" F=1.1×1019N

localid="1649397341555" G=6.67×10-11Nm2kg-2

m=9.4×1021kg

localid="1649397362538" r=1.5×108m

Substitute the values

localid="1649397565238" 1.1×1019N=6.67×10−11Nm2kg-29.4×1021kg1.5×108m2

⇒M=Mass of the distant planet =3.947×1023kg

Moon's orbital period in earth days is given by the expression,

T=2Ï€r3G(M+m)

localid="1649397468079" =2×3.141.5×108m36.67×10−11Nm2kg-23.947×1023kg+9.4×1021kg

=2248240s

localid="1649397499772" =2248240s3600s×24sdays

=26days

03

Final answer

The moon’s orbital period in earth days is

=26days

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