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Mass m1on the frictionless table of FIGURE EX8.13 is connected by a string through a hole in the table to a hanging mass m2. With what speed must m1 rotate in a circle of radius rif m2is to remain hanging at rest?

FIGURE EX8.13

Short Answer

Expert verified

The speed must m1rotate in a circle of radius r if m2 is to remain hanging at rest is

v=m2m1rg1

Step by step solution

01

Given information

Given in the question that, Mass m1on the frictionless table of FIGURE EX8.13 is connected by a string through a hole in the table to a hanging mass m2.

FIGURE EX8.13

02

Explanation

Here,

Here

Fc=Fw

Fc=m1v2r

FW=m2g

m1v2r=m2g

From the above equation we get,

v=m2m1rg

This is the speed must m1rotate in circle of radius rif m2is to remain handing at rest

v=m2m1rg

03

Final answer

The speed must m1rotate in a circle of radius rif m2 is to remain hanging at rest is

v=m2m1rg

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