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A laser emits 1.01019photons per second from an excited state with energy E2=1.17eV. The lower energy level is E1=0eV.

a. What is the wavelength of this laser?

b. What is the power output of this laser?

Short Answer

Expert verified

a. The wavelength is 1.06m.

b. The power output of this laser is1.9W.

Step by step solution

01

Part (a) Step 1 : Given Information

We have given that,

The lase emits 1.01019photons per second from an excited state with energy E2=1.17eV.

The lower energy level is E1=0eV.

We have to find the wavelength of this laser.

02

Part (a) Step 2 : Simplification

The wavelength is =hcE.

=hcE=1240eVnm1.17eV-0eV=1060nm=1.06m

localid="1650570984551" role="math" {h=6.62610-34Js,c=3108m/s}

The wavelength of laser is 1.06m.

03

Part (b) Step 1 : Given Information

We have given that,

The lase emits 1.01019photons per second from an excited state with energy E2=1.17eV.

The lower energy level is E1=0eV.

We have to find the power output of this laser.

04

Part (b) Step 2 : Simplification

The energy per photon is Eph=1.17eV=1.8710-19J. The power output of the laser is the number of photons per second times the energy per photon:

P=(1.01019s-1)(1.8710-19J)=1.9W(P=Power)

The power output of the laser is1.9W.

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