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Chapter 18: Q. 11 (page 510)

The temperature increases from 300 K to 1200 K as a gas undergoes

the process shown in FIGURE Q18.11. What is the final

pressure?

Short Answer

Expert verified

The final pressure of gas = 8 atm

Step by step solution

01

Visualisation

The ideal gas equation can be used in this problem.

In the ideal gas equation,

PV=nRT

Here, localid="1648461240466" P,V,n,R&Tare respectably pressure, volume, number of moles, universal gas constant and absolute temperature of gas.

In the given problem, V,n&Rare constants.

So,

localid="1648462419830" P鈭�TP2P1=T2T1P2=T2T1P1

Here, P1&T1are the initial pressure & temperature and P2&T2are the final pressure & temperature.

02

Step: 2  Calculation of the final pressure of gas

As given in the question,

T1=300K,T2=1200K,P1=2atm

Then,

P2=T2T1P1=1200K300K2atm=8atm

So, 8 atm is the final pressure of gas.

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Most popular questions from this chapter

A hollow aluminum sphere with outer diameter 10.0 cm has a

mass of 690 g. What is the sphere鈥檚 inner diameter?

The mercury manometer shown in FIGURE P18.56 is attached

to a gas cell. The mercury height h is 120 mm when the cell is

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Hint: The right tube of the manometer is much narrower than the

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a. What is the piston height hif the temperature is 30掳C?

b. How far does the piston move if the temperature is increased by 100掳C?

The U-shaped tube in FIGURE P18.57 has a total length of 1.0m. It is open at one end, closed at the other, and is initially filled with air at 20掳Cand1.0atmpressure.

Mercury is poured slowly into the open end without letting any air escape, thus compressing the air. This is continued until the open side of the tube is completely filled with mercury. What is the length Lof the column of mercury?

A rigid container holds 2.0molof gas at a pressure of 1.0atmand a temperature of 30掳C.

a. What is the container鈥檚 volume?

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