91影视

Theideal gas law shows the relationship between the four state variables for an ideal gas, namely the volume $V$of the container, the pressure $p$exerted on the gas, the temperature $T$of the gas, and the number of moles $n$of the gas in the container.

The ideal gas law is given by $PV=nRT$
Where $R$is the universal gas constant and in units of SI its value is $8.31J/mol.K$
Solve this for $V$we get : $V=\frac{nRT}{P}$

Temperature must be expressed in Kelvin and pressure in Pascals, so we must convert the units from Celsius. The conversion between the Celsius scale and the Kelvin scale is given by $T_K=T_C+273$

(a) Substitute the value for$T_C=30掳C$ to get
$$\begin{gathered} T_C=T_C+273 \\ =30掳C+273 \\ =303K \end{gathered}$$
To calculate the pressure in $Pa$, we use the following formula $$\begin{gathered} p=(1atm)\frac{1.01325x{10}^{5}Pa}{1atm}5Pa) \\ =1.01325x{10}^{5}Pa \end{gathered}$$
Now we substitute the values for $n,R,T\mathrm{and}p$into the equation$V=\frac{nRT}{P}$ to get:

(b) As can be seen from the ideal gas law, pressure $p$is directly proportional to temperature$T$. Thus, if the volume is constant for the same gas, we can obtain the relationship for two points in time as follows.
$$\begin{gathered} \frac{p_2}{p_1}=\frac{T_2}{T_1} \\ 鈬�p_2=\left(\frac{T_2}{T_1}\right)p_1 \end{gathered}$$
With $T鈧�=130掳+273=403K,T鈧�=303K,\mathrm{and}p鈧�=1atm$. It follows that :
$$\begin{gathered} p_2=(\frac{403K}{303K})(1atm) \\ =\mathbf{1}\mathbf{.}\mathbf{33}\mathbf{}\mathit{a}\mathit{t}\mathit{m}\mathbf{} \end{gathered}$$