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Chapter 38: Q1Q (page 1180)

Photon A has twice the energy of photon B. (a) Is the momentum of A less than, equal to, or greater than that of B? (b) Is the wavelength of A less than, equal to, or greater than that of B?

Short Answer

Expert verified

a) The momentum of A is greater than the momentum of B.

b) The wavelength of A is less than the wavelength of B.

Step by step solution

01

Introduction

Monochromatic lights are single-wavelength light, where mono refers to single, and chroma means colour. Visible light of a narrow band of wavelengths is classified as monochromatic lights. It features a wavelength within a short wavelength range.

02

(a) Determine the greatest wavelength of light

Here, EA=2EB

But the momentum of the photon p=Ec

E is the Energy of the photon

c is the speed of the light (which is a constant).

As EA=2EB

鈬�EA>Ea鈬�EAc>EBc鈬�pA>pB

Therefore, the momentum of A is greater than the momentum of B.

03

(b) Determine region of the electromagnetic spectrum

Here, EA=2EB

localid="1663058432865" 鈬�EA>EB

But energy E=hv, where h is Planck's constant

Frequency of light, 谓=hc位

鈭�E=hc位EA>EB鈬�hc位A>hc位B鈬�位A<位B

Therefore, wavelength of A is less than the wavelength of B.

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