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A helium–neon laser emits red light at wavelength λ=633nmin a beam of diameter 3.5 mm and at an energy-emission rate of 5.0 mW. A detector in the beam’s path totally absorbs the beam. At what rate per unit area does the detector absorb photons?

Short Answer

Expert verified

The rate of absorption of photon per unit area is1.7×1021photons/m2.s

Step by step solution

01

Describe the expression of energy of the photon

The energy Eof a photon of wavelengthλ is given by,

E=hcλ

Here, h is the Planck’s constant, and c is the speed of light.

02

Determine the rate of absorption of photon per unit area 

Assume that the protons are emitted by a rate R from the sodium lamp. Then, the power P of the sodium lamp is equal to the product of rate R and the energy of each photon E.

P=REP=RhcλR=pλhc…… (1)

Divide the rate R by area of the beam.

RA=Pλhc×π4d2=4Pλπd2hc…… (2)

Therefore, the rate of absorption of photon per unit area is1.7×1021photons/m2.s

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