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Chapter 38: Q15P (page 1182)

Light strikes a sodium surface, causing photoelectric emission. The stopping potential for the ejected electrons is 50 V, and the work function of sodium is 2.2 eV. What is the wavelength of the incident light?

Short Answer

Expert verified

The wavelength of the incident light is 172nm.

Step by step solution

01

Describe the expression for stopping voltage:

The expression of stopping voltage is given by,

Vstop=hef-桅e Vstop=hc位-桅e 鈥�.. (1)

Here, h is Planck鈥檚 constant, 位is wavelength, e is charge of electron,桅is work function, and c is the speed of light.

02

Determine the wavelength of the incident light:

Consider the given data as below.

The charge,e=1.6脳10-19C

The work function of sodium, 桅=2.2eV

The stopping potential for the ejected electrons, Vstop=5V

Plank鈥檚 constant, h=6.626脳10-34J路s

Speed of light, c=3脳108m/s

put above values in eq 1.

Simplify further for wavelength as below.

位=12.423脳10-77.2V=1.72脳10-7m=172脳10-9m=172nm

Hence, the wavelength of the incident light is 172 nm.

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