91影视

Mean =$25掳C$

Standard deviation =$2掳C$

The sample standard deviation is measured in the same units as the original data.

We have 渭 = $25掳C$and $蟽=2掳C$

Also we know that $掳F=(\frac{9}{5})掳C+32......\left(1\right)$

Temperature conversion from Celsius to Fahrenheit

The following formula is used to compute the pool's average temperature in Fahrenheit:$$\begin{gathered} 渭=25掳C \\ =(\frac{9}{5})脳25+32(u\sin gequation(1\left)\right) \\ =77掳F \end{gathered}$$

We just multiply the standard deviation in degrees Celsius by $\frac{9}{5}$ to get the standard deviation. Because the addition of$32$ only changes the distribution and has no effect on the spread, we get:$$\begin{gathered} 蟽=2掳C \\ =\left(\frac{9}{5}\right)脳2 \\ =3.6掳F \end{gathered}$$

As a result, the swimming pool's mean temperature is $u=77掳F$, and the standard deviation is $蟽=3.6掳F$

Therefore, the mean temperature is $u=77掳F$ and the standard deviation is $蟽=3.6掳F$