91Ó°ÊÓ

The average height of the team's players is $76$ inches. In the team's height distribution, Brent's height corresponds to a$z-$score of $0.85$

The value that has been standardized ($z-$score) The standardized value of$x$ is $z=\frac{x−mean}{s\tan darddeviation}$ if $x$is an observation from a distribution with known mean and standard deviation. A $z-$score is a term used to describe a standardized value.

Summary data from computer output and a dot graphic of the class's height distribution. The standardized score for $x$ is, if $x$ is an observation from a distribution with known mean and standard deviation. $z=\frac{x−mean}{s\tan darddeviation}$

As a result, it is stated that, $$\begin{gathered} z−score=-0.85 \\ x=76inches \\ \frac{−0.85}{1}=\frac{74−76}{S_x} \\ \frac{−0.85S_x}{−0.85}=\frac{2}{−0.85} \\ {S}_x=2.35inches \end{gathered}$$