91影视

The distribution of heights for $15$-year-old males is symmetric, single-peaked, and bell-shaped.

z-score of $0$corresponds to a Height$=170cm$
z-score of$1$corresponds to a height oflocalid="1649750294635" $=177.5cm$

The mean of the standard normal distribution is $0$.

$0$ is the mean of the standard normal distribution.
Accordingly, the mean of the normal height distribution is zero with a $z$-score of$0$:

$渭=170\mathrm{cm}$

$1$is the standard normal distribution.

A standard deviation for a normal height distribution is then equal to the difference between the $z-$score of $1$corresponding to the mean and the standard deviation:

$蟽=|渭-177.5|=7.5\mathrm{cm}$

The distribution of heights for$15-$year-old males is symmetric, single-peaked, and bell-shaped.

$z-$score of $0$corresponds to the height$=170cm$

$z-$score of $1$corresponds to the height $=177.5cm$

Given:

$z=2.5$

1a Result exercise is:

localid="1649943599620" $$\begin{gathered} 渭=170\mathrm{cm} \\ 蟽=7.5\mathrm{cm} \end{gathered}$$

A $z-$score is the mean multiplied by a $z-$score plus a standard deviation:

localid="1650000254221" $$\begin{gathered} x=渭+z蟽 \\ =170\mathrm{cm}+2.5(7.5\mathrm{cm}) \\ =188.75\mathrm{cm} \end{gathered}$$