/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 The paper "On the Nature of Cree... [FREE SOLUTION] | 91Ó°ÊÓ

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The paper "On the Nature of Creepiness" (New Ideas in Psychology [2016]: 10-15) describes a study to investigate what people think is "creepy." Each person in a sample of women and a sample of men were asked to do the following: Imagine a close friend of yours whose judgement you trust. Now imagine that this friend tells you that she or he just met someone for the first time and tells you that the person was creepy. The people in the samples were then asked whether they thought the creepy person was more likely to be a male or a female. Of the 1029 women surveyed, 980 said they thought it was more likely the creepy person was male, and 298 of the 312 men surveyed said they thought it was more likely the creepy person was male. Is there convincing evidence that the proportion of women who think the creepy person is more likely to be male is different from this proportion for men? For purposes of this exercise, you can assume that the samples are representative of the population of adult women and the population of adult men. Test the appropriate hypotheses using a significance level of 0.05

Short Answer

Expert verified
In conclusion, using a significance level of 0.05, there is no convincing evidence to suggest that the proportion of women who think the creepy person is more likely to be male is different from this proportion for men. The hypothesis test resulted in a P-value of 0.6456, which is greater than the significance level, leading us to fail to reject the null hypothesis.

Step by step solution

01

State the Null and Alternative Hypotheses

Let p1 be the proportion of women who think the creepy person is more likely to be male, and p2 be the proportion of men who think the creepy person is more likely to be male. The null and alternative hypotheses are defined as follows: Null Hypothesis (H0): p1 = p2 Alternative Hypothesis (Ha): p1 ≠ p2
02

Compute the Test Statistic

To compute the test statistic, we use the formula for the difference of proportions: Z = \(\frac{(\hat{p}_1 - \hat{p}_2) - 0}{\sqrt{\frac{\hat{p}(1-\hat{p})}{n_1} + \frac{\hat{p}(1-\hat{p})}{n_2}}}\) Where \(\hat{p}_1\) and \(\hat{p}_2\) are the sample proportions of women and men who think the creepy person is more likely to be male, n1 and n2 are the respective sample sizes, and \(\hat{p}\) is the combined proportion of both samples: \(\hat{p}_1 = \frac{980}{1029}\) \(\hat{p}_2 = \frac{298}{312}\) \(\hat{p} = \frac{980 + 298}{1029 + 312}\)
03

Calculate the Test Statistic and P-value

Using the given data and the formulas in Step 2, we can compute the test statistic: \(\hat{p}_1 = 0.9524\) \(\hat{p}_2 = 0.9551\) \(\hat{p} = 0.9531\) Z = \(\frac{(0.9524 - 0.9551) - 0}{\sqrt{\frac{0.9531(1-0.9531)}{1029} + \frac{0.9531(1-0.9531)}{312}}}\) Z ≈ -0.46 Now, we can find the P-value associated with this test statistic, which corresponds to the area in the tails of the standard normal distribution: P-value = 2 * P(Z < -0.46) = 2 * 0.3228 = 0.6456
04

Compare the P-value to the Significance Level

Now, we will compare the P-value to the significance level (α = 0.05): Since the P-value (0.6456) is greater than the significance level (0.05), we fail to reject the null hypothesis.
05

Make a Conclusion

Based on the hypothesis test, we fail to reject the null hypothesis that the proportion of women who think the creepy person is more likely to be male is the same as this proportion for men. Therefore, there is not convincing evidence to suggest that the proportions are different for men and women.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Difference of Proportions
When you're dealing with the difference of proportions in hypothesis testing, you're comparing two separate groups to see if a particular trait is more common in one than the other. In this exercise, the goal is to compare the proportion of women and men who think a creepy person is more likely to be male. To do this, we calculate the sample proportions from each group:
  • For women: 980 out of 1029 believe a creepy person is more likely male, so the proportion is \( \hat{p}_1 = \frac{980}{1029} \).
  • For men: 298 out of 312 believe this, so the proportion is \( \hat{p}_2 = \frac{298}{312} \).
Once you have these, you determine if there's a significant difference between them by using a test statistic.
Formulating the Null Hypothesis
The null hypothesis is the starting point for any hypothesis test. It assumes that there is no effect or no difference—essentially, it's the status quo. For this particular exercise, the null hypothesis (H0) is that the proportion of women who think the creepy person is male is equal to the proportion of men who think the same: \[ H_0: p_1 = p_2 \] This hypothesis sets the ground for statistical testing. If your data provides enough evidence against this assumption, then we can consider alternative hypotheses.
Considering the Alternative Hypothesis
In contrast to the null hypothesis, the alternative hypothesis explores what you might expect if your initial hypothesis is not correct. In this case, our alternative hypothesis (Ha) states that the proportions are not equal: \[ H_a: p_1 eq p_2 \] This suggests there's some difference between how men and women perceive gender in creepy people. When testing hypotheses, rejecting the null hypothesis in favor of the alternative hypothesis indicates that such a difference exists. This is only done if there's sufficient statistical evidence to support the claim based on your data.
Calculating the P-value
A p-value helps you determine the significance of your results in hypothesis testing. In simpler terms, it's a way of quantifying the probability of finding your observed results—or something more extreme—if the null hypothesis is true. In this situation, you'd first calculate the test statistic using your sample data and then find the corresponding p-value from the standard normal distribution.For this problem:
  • The combined sample proportion \( \hat{p} \) is found by pooling the data from both groups.
  • The Z test statistic is calculated to determine how much \( \hat{p}_1 \) and \( \hat{p}_2 \) differ from each other under the null hypothesis.
  • The p-value is then determined by finding the area under the curve beyond this Z value.
A p-value greater than your significance level (in this case, 0.05) suggests you don't have enough evidence to reject the null hypothesis, meaning you may conclude there's no strong overall difference between these gender proportions.

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Most popular questions from this chapter

The article "Most Women Oppose Having to Register for the Draft" (February \(10,2016,\) www.rasmussenreports. com, retrieved December 15,2016 ) describes a survey of likely voters in the United States. The article states that \(36 \%\) of those in a representative sample of male likely voters and \(21 \%\) of those in a representative sample of female likely voters said that they thought the United States should have a military draft. Suppose that these percentages were based on independent random samples of 500 men and 500 women. Use a significance level of 0.01 to determine if there is convincing evidence that the proportion of male likely voters who think the United States should have a military draft is different from this proportion for female likely voters.

The article "Footwear, Traction, and the Risk of Athletic Injury" (January \(2016,\) www.lermagazine.com/article/footwear -traction-and-the-risk-of-athletic-injury, retrieved December \(15,\) 2016) describes a study in which high school football players were given either a conventional football cleat or a swivel disc shoe. Of 2373 players who wore the conventional cleat, 372 experienced an injury during the study period. Of the 466 players who wore the swivel disc shoe, 24 experienced an injury. The question of interest is whether there is evidence that the injury proportion is smaller for the swivel disc shoe than it is for conventional cleats. a. What are the two treatments in this experiment? b. The article didn't state how the players in the study were assigned to the two groups. Explain why it is important to know if they were assigned to the groups at random. c. For purposes of this example, assume that the players were randomly assigned to the two treatment groups. Carry out a hypothesis test to determine if there is evidence that the injury proportion is smaller for the swivel disc shoe than it is for conventional cleats. Use a significance level of 0.05 .

Gallup surveyed adult Americans about their consumer debt ("Americans' Big Debt Burden Growing, Not Evenly Distributed," February 4, 2016, www.gallup.com, retrieved December 15,2016 ). They reported that \(47 \%\) of millennials (those born between 1980 and 1996 ) and \(61 \%\) of Gen Xers (those born between 1965 and 1971 ) did not pay off their credit cards each month and therefore carried a balance from month to month. Suppose that these percentages were based on representative samples of 450 millennials and 300 Gen Xers. Is there convincing evidence that the proportion of Gen Xers who do not pay off their credit cards each month is greater than this proportion for millennials? Test the appropriate hypotheses using a significance level of 0.05

The report "Audience Insights: Communicating to Teens (Aged 12-17)" (2009, www.cdc.gov) described teens' attitudes about traditional media, such as TV, movies, and newspapers. In a representative sample of American teenage girls, \(41 \%\) said newspapers were boring. In a representative sample of American teenage boys, \(44 \%\) said newspapers were boring. Sample sizes were not given in the report. a. Suppose that the percentages reported were based on samples of 58 girls and 41 boys. Is there convincing evidence that the proportion of those who think that newspapers are boring is different for teenage girls and boys? Carry out a hypothesis test using \(\alpha=.05\). b. Suppose that the percentages reported were based on samples of 2000 girls and 2500 boys. Is there convincing evidence that the proportion of those who think that newspapers are boring is different for teenage girls and boys? Carry out a hypothesis test using \(\alpha=0.05\). c. Explain why the hypothesis tests in Parts (a) and (b) resulted in different conclusions.

A headline that appeared in Woman's World stated "Black Currant Oil Curbs Hair Loss!" (Woman's World, April 4, 2016). This claim was based on an experiment described in the paper "Effect of a Nutritional Supplement on Hair Loss in Women" (Journal of Cosmetic Dermatology [2015]: 76-82). In this experiment, women with stage 1 hair loss were assigned at random to one of two groups. One group was a control group who did not receive a nutritional supplement. Of the 39 women in this group, 20 showed increased hair density at the end of the study period. Those in the second group received a nutritional supplement that included fish oil, black currant oil, vitamin E, vitamin C, and lycopene. Of the 80 women in the supplement group, 70 showed increased hair density at the end of the study period. a. Is there convincing evidence that the proportion with increased hair density is greater for the supplement treatment than for the control treatment? Test the appropriate hypotheses using a 0.01 significance level. b. Write a few sentences commenting on the headline that appeared in Woman's World. c. Based on the description of the actual experiment and the result from your hypothesis test in Part (a), suggest a more appropriate headline.

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