/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 According to a survey of a rando... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

According to a survey of a random sample of 2278 adult Americans conducted by the Harris Poll ("Do Americans Prefer Name Brands or Store Brands? Well, That Depends" (theharrispoll.com, February 11, 2015, retrieved November 29,2016 ), 1162 of those surveyed said that they prefer name brands to store brands when purchasing frozen vegetables. Suppose that you want to use this information to determine if there is convincing evidence that a majority of adult Americans prefer name-brand frozen vegetables over store brand frozen vegetables. a. What hypotheses should be tested in order to answer this question? b. The \(P\) -value for this test is 0.173 . What conclusion would you reach if \(\alpha=0.05 ?\)

Short Answer

Expert verified
The hypotheses to be tested are H0: p ≤ 0.5 (no majority prefers name-brand frozen vegetables) and H1: p > 0.5 (majority prefers name-brand frozen vegetables). With a given p-value of 0.173 and α = 0.05, since 0.173 > 0.05, we fail to reject H0. Hence, there is insufficient evidence to claim that a majority of adult Americans prefer name-brand frozen vegetables over store-brand ones.

Step by step solution

01

Formulate the hypotheses

Let p represent the proportion of adult Americans who prefer name-brand frozen vegetables. We are interested in finding if the majority of adult Americans (i.e., more than 50%) prefer name-brands. So we can formulate the hypotheses as: H0: p ≤ 0.5 (There is no majority who prefer name-brand frozen vegetables) H1: p > 0.5 (There is a majority who prefer name-brand frozen vegetables)
02

Evaluate the p-value

The p-value for the test is given as 0.173. The given significance level (α) is 0.05. Now, let's interpret the p-value and make a decision based on the given value of α.
03

Make a decision based on p-value and α

Since the p-value = 0.173 is greater than α = 0.05, we fail to reject the null hypothesis (H0). In other words, there is not enough evidence at the 5% significance level supporting the claim that a majority of adult Americans prefer name-brand frozen vegetables over store-brand frozen vegetables.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null and Alternative Hypotheses
When we conduct hypothesis testing in statistics, we start by clearly stating two opposing hypotheses. The null hypothesis (0) represents a default position that there is no effect or no difference. It's a statement of no change or status quo that we presume to be true until we have enough evidence to support the alternative hypothesis. In the context of our frozen vegetables preference study, the null hypothesis is that half or fewer American adults prefer name-brand frozen vegetables, symbolized as 0: p leq 0.5.

The alternative hypothesis (1), on the other hand, is a statement we're trying to find evidence for. In this case, it's the belief that more than 50% of adult Americans prefer name-brand frozen vegetables, indicated as 1: p > 0.5. It's important to note that statistical tests are designed to test the null hypothesis, not to prove the alternative hypothesis. Thus, in hypothesis testing, we either reject 0 in favor of 1, or we fail to reject 0, implying that the data does not provide strong support for 1.
P-value Interpretation
The p-value is a critical concept in hypothesis testing that helps determine whether to reject the null hypothesis. It is the probability of observing your data, or something more extreme, assuming that the null hypothesis is true. A low p-value suggests that observing such data would be very unlikely if 0 were true and thus provides evidence against 0.

In our example, the p-value is calculated to be 0.173. This means that there is a 17.3% probability of finding a sample proportion as extreme as the one observed, or more, if in fact only 50% of the population prefers name-brand vegetables. Since this p-value is comparatively high, it suggests that such an outcome would not be particularly unusual under the null hypothesis. Therefore, it does not provide sufficient grounds to reject 0. In simpler terms, the data does not present strong evidence that a majority of adult Americans prefer name-brand frozen vegetables over store brands.
Significance Level
The significance level () is a threshold set by the researcher to decide whether to reject the null hypothesis. It's a measure of how stringent or tolerant we are of making a type I error, which is rejecting 0 when it's in fact true. Common levels of significance include 0.01, 0.05, and 0.10, but 0.05 is perhaps the most widely used.

In the frozen vegetables exercise, the significance level was set at =0.05, indicating a 5% risk of concluding that a majority of adult Americans prefer name-brand frozen vegetables when they actually do not. With a p-value of 0.173, which is higher than the significance level, we maintain our position of insufficient evidence to reject the null hypothesis. Simply put, the findings of the survey do not meet the rigorous criteria required to confidently assert that a majority of adult Americans have a preference for name-brand frozen vegetables.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A county commissioner must vote on a resolution that would commit substantial resources to the construction of a sewer in an outlying residential area. Her fiscal decisions have been criticized in the past, so she decides to take a survey of residents in her district to find out if they favor spending money for a sewer system. She will vote to appropriate funds only if she can be reasonably sure that a majority of the people in her district favor the measure. What hypotheses should she test?

How accurate are DNA paternity tests? By comparing the DNA of the baby and the DNA of a man that is being tested, one maker of DNA paternity tests claims that their test is \(100 \%\) accurate if the man is not the father and \(99.99 \%\) accurate if the man is the father (IDENTIGENE, www.dnatesting .com/paternity-test-questions/paternity-test-accuracy/, retrieved November 16,2016 ). a. Consider using the result of this DNA paternity test to decide between the following two hypotheses: \(H_{0}:\) a particular man is not the father \(H:\) a particular man is the father In the context of this problem, describe Type I and Type II errors. (Although these are not hypotheses about a population characteristic, this exercise illustrates the definitions of Type I and Type II errors.) b. Based on the information given, what are the values of \(\alpha\), the probability of a Type I error, and \(\beta\), the probability of a Type II error?

Refer to the instructions given prior to Exercise \(10.47 .\) The article "iPhone Can Be Addicting, Says New Survey" (www.msnbc.com, March 8,2010 ) described a survey administered to 200 college students who owned an iPhone, One of the questions on the survey asked students if they slept with their iPhone in bed with them. You would like to use the data from this survey to determine if there is convincing evidence that a majority of college students with iPhones sleep with their phones.

CareerBuilder.com conducted a survey to learn about the proportion of employers who perform background checks when evaluating a candidate for employment ("Majority of Employers Background Check Employees...Here's Why," November \(17,\) \(2016,\) retrieved November 19,2016 ). Suppose you are interested in determining if the resulting data provide strong evidence in support of the claim that more than two-thirds of employers perform background checks. To answer this question, what null and alternative hypotheses should you test? (Hint: See Example \(10.4 .)\)

The article "Public Acceptability in the UK and the USA of Nudging to Reduce Obesity: The Example of Reducing Sugar-Sweetened Beverages" (PLOS One, June 8,2016 ) describes a survey in which each person in a representative sample of 1082 adult Americans was asked about whether they would find different types of interventions acceptable in an effort to reduce consumption of sugary beverages. When asked about a tax on sugary beverages, 459 of the people in the sample said they thought that this would be an acceptable intervention. These data were used to test \(H_{0}: p=0.5\) versus \(H_{a^{*}}: p<0.5\) and the null hypothesis was rejected. a. Based on the hypothesis test, what can you conclude about the proportion of adult Americans who think that taxing sugary beverages is an acceptable intervention in an effort to reduce consumption of sugary beverages? b. Is it reasonable to say that the data provide strong support for the alternative hypothesis? c. Is it reasonable to say that the data provide strong evidence against the null hypothesis?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.