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91Ó°ÊÓ

A county commissioner must vote on a resolution that would commit substantial resources to the construction of a sewer in an outlying residential area. Her fiscal decisions have been criticized in the past, so she decides to take a survey of residents in her district to find out if they favor spending money for a sewer system. She will vote to appropriate funds only if she can be reasonably sure that a majority of the people in her district favor the measure. What hypotheses should she test?

Short Answer

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The county commissioner should test the following hypotheses: H0: The majority of people in the district do NOT favor spending money on a sewer system. H1: The majority of people in the district DO favor spending money on a sewer system. To make a decision, the commissioner can conduct a hypothesis test using the proportions of residents who favor the sewer project and those who do not. Based on the calculated test statistic \(z\) and a chosen significance level \(\alpha\), she can determine if there is enough evidence to reject the null hypothesis and support the alternative hypothesis that a majority of the residents in her district favor spending money on the sewer system project.

Step by step solution

01

Determine the Null and Alternative Hypotheses

In statistical hypothesis testing, we first need to determine the null hypothesis (H0) and the alternative hypothesis (H1). In this case, H0 will represent no majority support for the sewer system project, while H1 will represent majority support for the project. H0: The majority of people in the district do NOT favor spending money on a sewer system. H1: The majority of people in the district DO favor spending money on a sewer system.
02

Conduct the Survey

The county commissioner will conduct a survey to gather data from a representative sample of residents in her district. The survey should include a question about whether they support the sewer project or not. It is important that the sample is large enough and unbiased to draw reliable conclusions.
03

Collect and Analyze the Data

Once the survey is completed, the commissioner should collect and analyze the results. Calculate the proportions of residents who favor the sewer project and those who do not. Let \(p\) represent the proportion of residents who favor the project, and \(n\) be the total number of respondents in the survey. Then, calculate the test statistic for the proportion: \[z = \frac{(\hat{p} - p_0)}{\sqrt{\frac{p_0(1-p_0)}{n}}}\] Where \(\hat{p}\) is the observed proportion in the survey, \(p_0\) is the assumed proportion under the null hypothesis (in this case 0.5, as the majority means greater than 50%), and the denominator represents the standard error.
04

Determine the Rejection Region

To make a decision on whether or not to reject the null hypothesis, the commissioner should determine the rejection region, which depends on the chosen significance level \(\alpha\). A common choice for \(\alpha\) is 0.05 (5%). With a one-tailed test, the rejection region will be in the upper tail of the distribution, corresponding to people supporting the sewer project. Find the critical value \(z_\alpha\) for the chosen significance level \(\alpha\) and the corresponding rejection region.
05

Make a Decision Based on the Test Statistic

Compare the calculated test statistic \(z\) from Step 3 with the critical value \(z_\alpha\) from Step 4. If the test statistic falls in the rejection region (i.e., \(z > z_\alpha\)), the commissioner can conclude that there is enough evidence to reject the null hypothesis and support the alternative hypothesis that a majority of the residents in her district favor spending money on the sewer system project. If the test statistic does not fall in the rejection region, the commissioner cannot reject the null hypothesis, meaning there is not enough evidence to support the alternative hypothesis that the majority of residents favor the project. In this case, she should not vote for the appropriation of funds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In hypothesis testing, the null hypothesis (often denoted as \(H_0\)) acts as a starting point, or a default assumption that there is no effect or no difference. For the county commissioner considering the sewer system, the null hypothesis posits that a majority does not exist in favor of the project. This is expressed statistically as "less than or equal to 50% support".

The process of determining whether this null hypothesis can be rejected or not is central to the decision-making process. It allows the commissioner to objectively assess the data collected from the survey, putting aside personal biases or previous criticisms. Rejection of the null hypothesis leads to favoring the alternative hypothesis, indicating that the survey has provided enough evidence against the idea that there isn't majority support.
Alternative Hypothesis
The alternative hypothesis, denoted as \(H_1\), represents what we are trying to prove. In our case, it's the idea that there is indeed majority support among residents for the sewer project. This is typically what the survey aims to show - that more than 50% of residents favor the project.

If the analysis of survey results yields sufficient statistical evidence to reject the null hypothesis, the alternative hypothesis becomes the more likely explanation. It helps the decision-maker to understand whether there is enough backing from the district's populace to proceed with the allocation of funds. Thus, defining \(H_1\) guides the county commissioner to make an informed decision by focusing on the presence of significant support.
Survey Sampling
Survey sampling is about collecting opinions from a portion of the entire population to make inferences about the whole group. For the county commissioner's decision, a well-conducted survey is crucial. It requires selecting a representative sample of district residents to reflect the actual proportion of those who support or oppose the sewer project.

Let's break down some critical points about survey sampling:
  • Representative: The sample should mirror the diversity and characteristics of the entire population.
  • Unbiased: The selection process must be random to avoid skewing results.
  • Large Enough: A larger sample size increases the survey's reliability, providing more trustworthy results.

By ensuring the sample is representative, the commissioner minimizes errors in judgment when deciding based on survey data.
Test Statistic
The test statistic is a value derived from sample data that is used to make decisions about the null hypothesis. In this scenario, it measures the degree of support residents have for the sewer project.

The formula used here is for testing the proportion of residents favoring the project: \[ z = \frac{(\hat{p} - p_0)}{\sqrt{\frac{p_0(1-p_0)}{n}}} \]where:
  • \(\hat{p}\) is the observed proportion from the survey
  • \(p_0\) is the null hypothesis proportion, often 0.5 for majority hypothesis testing.
  • \(n\) is the sample size

This statistic helps the commissioner decide whether the observed data is extreme enough to reject the null hypothesis, it’s a key piece in the puzzle of hypothesis testing.
Significance Level
The significance level \(\alpha\) represents the probability of making a type I error, which is rejecting a true null hypothesis. For the county commissioner, choosing \(\alpha = 0.05\) sets the probability of wrongly determining that the majority supports the sewer project to 5%.

This level of significance, or threshold, helps define the rejection region for test statistics. If the computed test statistic falls within the rejection region, defined by a critical value \(z_\alpha\), the null hypothesis is rejected.
  • Common Choices: Typical values for \(\alpha\) are 0.05 or 0.01 depending on the confidence needed.
  • Decision-Making: A smaller \(\alpha\) reduces type I error risk, but increases type II error risk (failing to reject a false null hypothesis).

The chosen significance level thereby assists in balancing the decision-making risks involved in hypothesis testing.

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Most popular questions from this chapter

Past experience is that when individuals are approached with a request to fill out and return a particular questionnaire in a provided stamped and addressed envelope, the response rate is \(40 \%\). An investigator believes that if the person distributing the questionnaire were stigmatized in some obvious way, potential respondents would feel sorry for the distributor and thus tend to respond at a rate higher than \(40 \%\). To test this theory, a distributor wore an eye patch. Of the 200 questionnaires distributed by this individual, 109 were returned. Does this provide evidence that the response rate in this situation is greater than the previous rate of \(40 \%\) ? State and test the appropriate hypotheses using a significance plevel of 0.05 .

A study of treatment of hospitalized patients who develop pneumonia reported that 1 in \(5(20 \%)\) are readmitted to the hospital within 30 days after discharge ("Comparison of Therapist-Directed and Physician-Directed Respiratory Care in COPD Subjects with Acute Pneumonia," Respiratory Care \([2015]: 151-154)\) The study reported that 15 out of \(n=162\) hospital patients who had been treated for pneumonia using a respiratory therapist protocol were readmitted to the hospital within 30 days after discharge. You would like to use this sample data to decide if the proportion readmitted is less than 0.20 . a. What hypotheses should be tested? b. Discuss whether the conditions necessary for a largesample hypothesis test for one proportion are satisfied. c. The exact binomial test can be used even in cases when the sample size condition for the large-sample test is met.

The article "Streaming Overtakes Live TV Among Consumer Viewing Preferences" (Variety, April 22, 2015) states that "U.S. consumers are more inclined to stream entertain- ment from an internet service than tune in to live TV:" This statement is based on a survey of a representative sample of 2076 U.S. consumers. Of those surveyed, 1100 indicated that they prefer to stream TV shows rather than watch TV programs live. Do the sample data provide convincing evidence that a majority of U.S. consumers prefer to stream TV shows rather than to watch them live? Test the relevant hypotheses using a 0.05 significance level.

In the report "Healthy People 2020 Objectives for the Nation," The Centers for Disease Control and Prevention (CDC) set a goal of 0.341 for the proportion of mothers who will still be breastfeeding their babies one year after birth (www.cdc.gov/breastfeeding/policy /hp2020.htm, April 11, 2016, retrieved November 28, 2016). The CDC also estimated the proportion who were still being breastfed one year after birth to be 0.307 for babies born in 2013 (www.cdc.gov/breastfeeding /pdf/2016breastfeedingreportcard.pdf, retrieved November 28,2016) . This estimate was based on a survey of women who had given birth in 2013 . Suppose that the survey used a random sample of 1000 mothers and that you want to use the survey data to decide if there is evidence that the goal is not being met. Let \(p\) denote the population proportion of all mothers of babies born in 2013 who were still breast-feeding at 12 months. (Hint: See Example \(10.10 .)\) a. Describe the shape, center, and variability of the sampling distribution of \(\hat{p}\) for random samples of size 1000 if the null hypothesis \(H_{0}: p=0.341\) is true. b. Would you be surprised to observe a sample proportion as small as \(\hat{p}=0.333\) for a sample of size 1000 if the null hypothesis \(H_{0}: p=0.341\) were true? Explain why or why not. c. Would you be surprised to observe a sample proportion as small as \(\hat{p}=0.310\) for a sample of size 1000 if the null hypothesis \(H_{0}: p=0.341\) were true? Explain why or why not. d. The actual sample proportion observed in the study was \(p=0.307\). Based on this sample proportion, is there convincing evidence that the goal is not being met, or is the observed sample proportion consistent with what you would expect to see when the null hypothesis is true? Support your answer with a probability calculation.

USA TODAY (March 4, 2010) described a survey of 1000 women age 22 to 35 who work full time. Each woman who participated in the survey was asked if she would be willing to give up some personal time in order to make more money. To determine if the resulting data provided convincing evidence that the majority of women age 22 to 35 who work full time would be willing to give up some personal time for more money, what hypotheses should you test?

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