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The accompanying data came from a study of collusion inbidding within the construction industry (鈥淒etection ofCollusive Behavior,鈥 J. of Construction Engr. AndMgmnt, 2012: 1251鈥1258).

No.Bidders

No.Contracts

2

7

3

20

4

26

5

16

6

11

7

9

8

6

9

8

10

3

11

2

a. What proportion of the contracts involved at mostfive bidders? At least five bidders?

b. What proportion of the contracts involved betweenfive and 10 bidders, inclusive? Strictly between fiveand 10 bidders?

c. Construct a histogram and comment on interestingfeatures.

Short Answer

Expert verified

a.

The proportion of the contracts involved at most five bidders is 0.64.

The proportion of the contracts involved at least five bidders is 0.51.

b.

The proportion of the contracts between 5 and 10 bidders, inclusively is 0.49.

The proportion of the contracts strictly between 5 and 10 bidders is 0.31.

c.

Step by step solution

01

Given information

Thedatafrom a study of collusion in bidding within the construction industry is provided.

a.

The total number of contracts is 108.

Let X represents the number of Bidders.

02

Compute the proportion

The proportion of the contracts involved at most five bidders is computed as,

\(\begin{aligned}P\left( {X \le 5} \right) &= P\left( {X = 2} \right) + P\left( {X = 3} \right) + P\left( {X = 4} \right) + P\left( {X = 5} \right)\\ &= \frac{{n\left( {X = 2} \right) + n\left( {X = 3} \right) + n\left( {X = 4} \right) + n\left( {X = 5} \right)}}{N}\\ &= \frac{{7 + 20 + 26 + 16}}{{108}}\\ &= 0.638\\ &\approx 0.64\end{aligned}\)

Therefore, the proportion of the contracts involved at most five bidders is 0.64.

The proportion of the contracts involved at least five bidders is computed as,

\(\begin{aligned}P\left( {X \ge 5} \right) &= 1 - P\left( {X < 5} \right)\\ &= 1 - \left( {P\left( {X = 2} \right) + P\left( {X = 3} \right) + P\left( {X = 4} \right)} \right)\\ &= 1 - \left( {\frac{{n\left( {X = 2} \right) + n\left( {X = 3} \right) + n\left( {X = 4} \right)}}{N}} \right)\\ &= 1 - \frac{{7 + 20 + 26}}{{108}}\\ &= 1 - 0.49\\ &= 0.51\end{aligned}\)

Therefore, the proportion of the contracts involved at least five bidders is 0.51.

03

Given information

The datafrom a study of collusion in bidding within the construction industry is provided.

04

Compute the proportion

b.

The total number of contracts is 108.

Let X represents the number of Bidders.

The proportion of the contracts involved between 5 and 10 bidders, inclusively is computed as,

\(\begin{aligned}P\left( {5 \le X \le 10} \right) &= P\left( {X = 5} \right) + P\left( {X = 6} \right) + P\left( {X = 7} \right) + P\left( {X = 8} \right) + P\left( {X = 9} \right) + P\left( {X = 10} \right)\\ &= \frac{{n\left( {X = 5} \right) + n\left( {X = 6} \right) + n\left( {X = 7} \right)... + n\left( {X = 10} \right)}}{N}\\ &= \frac{{16 + 11 + 9 + 6 + 8 + 3}}{{108}}\\ &= 0.49\end{aligned}\)

Therefore, the proportion of the contracts between 5 and 10 bidders, inclusively is 0.49.

The proportion of the contracts involved strictly between 5 and 10 bidders is computed as,

\(\begin{aligned}P\left( {5 < X < 10} \right) &= P\left( {X = 6} \right) + P\left( {X = 7} \right) + P\left( {X = 8} \right) + P\left( {X = 9} \right)\\ &= \frac{{n\left( {X = 6} \right) + n\left( {X = 7} \right) + n\left( {X = 8} \right) + n\left( {X = 9} \right)}}{N}\\ &= \frac{{11 + 9 + 6 + 8}}{{108}}\\ &= 0.31\end{aligned}\)

Therefore, the proportion of the contracts strictly between 5 and 10 bidders is 0.31.

05

Given information

The datafrom a study of collusion in bidding within the construction industry is provided.

06

Construct a histogram and state the features

c.

Steps to construct a histogram are,

1) Determine the frequency or the relative frequency.

2) Mark the class boundaries on the horizontal axis.

3) Draw a rectangle on the horizontal axis corresponding to the frequency or relative frequency.

The histogram is represented as,

The features that can be observed from the above histogram are,

1)The histogram is unimodal; this implies that there is only one mode; that is 4.

2)The distribution is positively skewed.

3)The typical value of x is 5.

4) There are no outliers present in the data.

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Most popular questions from this chapter

The National Health and Nutrition Examination Survey (NHANES) collects demographic, socioeconomic, dietary, and health related information on an annual basis. Here is a sample of \({\rm{20}}\) observations on HDL cholesterol level \({\rm{(mg/dl)}}\) obtained from the \({\rm{2009 - 2010}}\) survey (HDL is 鈥済ood鈥 cholesterol; the higher its value, the lower the risk for heart disease):

\(\begin{array}{l}{\rm{35 49 52 54 65 51 51}}\\{\rm{47 86 36 46 33 39 45}}\\{\rm{39 63 95 35 30 48}}\end{array}\)

a. Calculate a point estimate of the population mean HDL cholesterol level.

b. Making no assumptions about the shape of the population distribution, calculate a point estimate of the value that separates the largest \({\rm{50\% }}\) of HDL levels from the smallest \({\rm{50\% }}\).

c. Calculate a point estimate of the population standard deviation.

d. An HDL level of at least \({\rm{60}}\) is considered desirable as it corresponds to a significantly lower risk of heart disease. Making no assumptions about the shape of the population distribution, estimate the proportion \({\rm{p}}\) of the population having an HDL level of at least \({\rm{60}}\).

The article cited in Example 1.2 also gave the accompanying strength observations for cylinders:

6.1

5.8

7.8

7.1

7.2

9.2

6.6

8.3

7.0

8.3

7.8

8.1

7.4

8.5

8.9

9.8

9.7

14.1

12.6

11.2


a. Construct a comparative stem-and-leaf display(see the previous exercise) of the beam and cylinder data, and then answer the questions in parts(b)鈥(d) of Exercise 10 for the observations oncylinders.

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A sample of 77 individuals working at a particular office wasselected and the noise level (dBA) experienced by each individual was determined, yielding the followingdata (鈥淎cceptable Noise Levels for Construction Site Offices,鈥 Building Serv. Engr. Research and Technology, 2009: 87鈥94).

55.3

55.3

55.3

55.9

55.9

55.9

55.9

56.1

56.1

56.1

56.1

56.1

56.1

56.8

56.8

57.0

57.0

57.0

57.8

57.8

57.8

57.9

57.9

57.9

58.8

58.8

58.8

59.8

59.8

59.8

62.2

62.2

63.8

63.8

63.8

63.9

63.9

63.9

64.7

64.7

64.7

65.1

65.1

65.1

65.3

65.3

65.3

65.3

67.4

67.4

67.4

67.4

68.7

68.7

68.7

68.7

69.0

70.4

70.4

71.2

71.2

71.2

73.0

73.0

73.1

73.1

74.6

74.6

74.6

74.6

79.3

79.3

79.3

79.3

83.0

83.0

83.0

Use various techniques discussed in this chapter to organize, summarize, and describe the data.

Blood cocaine concentration (mg/L) was determined both for a sample of individuals who had died from cocaine-induced excited delirium (ED) and for a sample of those who had died from a cocaine overdose without excited delirium; survival time for people in both groups was at most 6 hours. The accompanying data was read from a comparative boxplot in the article 鈥淔atal Excited Delirium Following Cocaine Use鈥 (J.

of Forensic Sciences, 1997: 25鈥31).

ED0 0 0 0 .1 .1 .1 .1 .2 .2 .3 .3

.3 .4 .5 .7 .8 1.0 1.5 2.7 2.8

3.5 4.0 8.9 9.2 11.7 21.0

Non-ED0 0 0 0 0 .1 .1 .1 .1 .2 .2 .2

.3 .3 .3 .4 .5 .5 .6 .8 .9 1.0

1.2 1.4 1.5 1.7 2.0 3.2 3.5 4.1

4.3 4.8 5.0 5.6 5.9 6.0 6.4 7.9

8.3 8.7 9.1 9.6 9.9 11.0 11.5

12.2 12.7 14.0 16.6 17.8

a. Determine the medians, fourths, and fourth spreads for the two samples.

b. Are there any outliers in either sample? Any extreme outliers?

c. Construct a comparative boxplot, and use it as a basis for comparing and contrasting the ED and non-ED samples.

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