/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Free solutions & answers for Probability And Statistics For Engineering And Sciences Chapter 13 - (Page 1) [step by step] 9781305251809 | 91Ó°ÊÓ

91Ó°ÊÓ

Chapter 13: Nonlinear and Multiple Regression

Q11E

Page 549

Buckling of a Thin Vertical Column In Example 4 of Section 5.2 we saw that when a constant vertical compressive force, or load, \(P\) was applied to a thin column of uniform cross section and hinged at both ends, the deflection \(y(x)\) is a solution of the BVP:

\(El\frac{{{d^2}y}}{{d{x^2}}} + Py = 0,y(0) = 0,y(L) = 0\)

(a)If the bending stiffness factor \(El\) is proportional to \(x\), then \(El(x) = kx\), where \(k\) is a constant of proportionality. If \(El(L) = kL = M\) is the maximum stiffness factor, then \(k = M/L\) and so \(El(x) = Mx/L\). Use the information in Problem 39 to find a solution of \(M\frac{x}{L}\frac{{{d^2}y}}{{d{x^2}}} + Py = 0,y(0) = 0,y(L) = 0\) if it is known that \(\sqrt x {Y_1}(2\sqrt {\lambda x} )\) is not zero at \(x = 0\).

(b) Use Table 6.4.1 to find the Euler load \({P_1}\) for the column.

(c) Use a CAS to graph the first buckling mode \({y_1}(x)\) corresponding to the Euler load \({P_1}\). For simplicity assume that \({c_1} = 1\) and \(L = 1\).

Q38E

Page 589

Column Bending Under Its Own Weight A uniform thin column of length \(L\), positioned vertically with one end embedded in the ground, will deflect, or bend away, from the vertical under the influence of its own weight when its length or height exceeds a certain critical value. It can be shown that the angular deflection \(\theta (x)\) of the column from the vertical at a point \(P(x)\) is a solution of the boundary-value problem:\(El\frac{{{d^2}\theta }}{{d{x^2}}} + \delta g(L - x)\theta = 0,\theta (0) = 0,\theta '(L) = 0,\) where \(E\) is Young’s modulus, \(I\) is the cross-sectional moment of inertia, \(\delta \) is the constant linear density, and \(x\) is the distance along the column measured from its base. See Figure 6.4.7. The column will bend only for those values of \(L\) for which the boundary-value problem has a nontrivial solution.

(a) Restate the boundary-value problem by making the change of variables \(t = L - x\). Then use the results of a problem earlier in this exercise set to express the general solution of the differential equation in terms of Bessel functions.

(b) Use the general solution found in part (a) to find a solution of the BVP and an equation which denes the critical length \(L\), that is, the smallest value of \(L\)for which the column will start to bend.

(c) With the aid of a CAS, find the critical length \(L\) of a solid steel rod of radius \(r = 0.05in,\delta g = 0.28Alb/in,E = 2.6 \times 1{0^7}lb/i{n^2},A = \pi {r^2}\)and \(I = \frac{1}{4}\pi {r^4}\).

Access millions of textbook solutions in one place

  • Access over 3 million high quality textbook solutions
  • Access our popular flashcard, quiz, mock-exam and notes features
  • Access our smart AI features to upgrade your learning
Access millions of textbook solutions in one place

Recommended explanations on Math Textbooks