91影视

Upper 鈥� tailed test

n = 12

\({s_ + } = 56\)

The p-value is the probability of obtaining the value if the test statistic, or a value more extreme, assuming that the null hypothesis is true. The P-value is the number (or interval) in the column\({P_0}({S_ + } \ge {c_1})\)of the wilcoxon signed 鈥� rank table in the appendix that contain the\({s_ + }\)-value in the column\({c_1}\)in the row n = 12

P = 0.102

Upper 鈥� tailed test

n = 12

\({s_ + } = 62\)

The p-value is the probability of obtaining the value if the test statistic, or a value more extreme, assuming that the null hypothesis is true. The P-value is the number (or interval) in the column\({P_0}({S_ + } \ge {c_1})\)of the wilcoxon signed 鈥� rank table in the appendix that contain the\({s_ + }\)-value in the column\({c_1}\)in the row n = 12

0.026 < P < 0.046

lower 鈥� tailed test

n = 12

\({s_ + } = 20\)

Determine the higest possible sum rocks:

\(\sum\limits_{i = 1}^{12} i = \frac{{12\left( {12 + 1} \right)}}{2} = 78\)

The\({s_ + }\)-value corresponding to an upper-tailed test then highest possible sun decresed by\({s_ + }\)- value corresponding to a lower tailed test

78 鈥� 20 = 58

The p-value is the probability of obtaining the value if the test statistic, or a value more extreme, assuming that the null hypothesis is true. The P-value is the number (or interval) in the column\({P_0}({S_ + } \ge {c_1})\)of the wilcoxon signed 鈥� rank table in the appendix that contain the\({s_ + }\)-value in the column\({c_1}\)in the row n = 12

0.055 < P < 0.102

Two 鈥� tailed test

n = 25

\({s_ + } = 300\)

Thez-score is the value of the test static decreased by the mean, divided by the standard deviation:

\(z = \frac{{{S_ + } - n\left( {n + 1} \right)/4}}{{\sqrt {n\left( {n + 1} \right)\left( {2n + 1} \right)/24} }} = \frac{{300 - 25\left( {25 + 1} \right)/4}}{{\sqrt {25\left( {25 + 1} \right)\left( {2\left( {25} \right) + 1} \right)/24} }} \approx - 3\)

The p-value is the probability of obtaining the value more extreme or equal to the standardized test static z, assuming that the null hypothesis is true. Determine the probability using normal table in appendix

\(P = P\left( {Z < - 3.70ORZ > 3.70} \right) = 2P\left( {Z < - 3.70} \right) \approx 2\left( 0 \right) = 0\)

P = 0