/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q6E Use the large-sample version of ... [FREE SOLUTION] | 91影视

91影视

Use the large-sample version of the Wilcoxon test at significance level .05 on the data of Exercise 37 in Section 9.3 to decide whether the true mean difference between outdoor and indoor concentrations exceeds .20.

Short Answer

Expert verified

Because of the fact that

P(S+ \( \ge \)c1)=0.005

P>0.01= 伪

Do not reject null hypothesis.

Step by step solution

01

Wilcoxon rank sum test

The Wilcoxon test is based upon ranking the nA + nB observations of the combined sample. Each observation has a rank: the smallest has rank 1, the 2nd smallest rank 2, and so on. The Wilcoxon rank-sum test statistic is the sum of the ranks for observations from one of the samples.

02

Finding the value of P

The hypothesis of interest are

H0:饾泹=0,

Versus alternative

HD:饾泹D>0,

The following table represents the value required to compute the test statistic value and corresponding P value:

i

\(x_i^1\)

\(x_i^2\)

\({y_i} = x_i^1 - x_i^2\)

\(rank({y_i})\)

\(sign({y_i})\)

1

1509

1498

11

2

1

2

1418

1254

164

7

1

3

1561

1336

225

9

1

4

1556

1565

-9

1

-1

5

2169

2000

169

8

1

6

1760

1318

442

12

1

7

1098

1410

-312

10

-1

8

1198

1129

69

4

1

9

1479

1342

137

5

1

10

1281

1124

157

6

1

11

1414

1468

-54

3

-1

12

1954

1604

350

11

1

13

2174

1722

452

13

1

14

2058

1518

540

14

1

The test statistic value is

s+=91

The corresponding P-value is (the test is upper tailed)

P=2P0(S+ \( \ge \)14)

Because of the fact that

P(S+ \( \ge \)c1)=0.005

P>0.01= 伪

Do not reject null hypothesis.

Hence, the final answer is that it will not reject null hypothesis.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

High-pressure sales tactics or door-to-door salespeople can be quite offensive. Many people succumb to such tactics, sign a purchase agreement, and later regret their actions. In the mid-1970s, the Federal Trade Commission implemented regulations clarifying and extending the rights of purchasers to cancel such agreements. The accompanying data is a subset of that given in the article 鈥淓valuating the FTC Cooling-Off Rule鈥 (J. of Consumer Affairs, 1977: 101鈥106). Individual observations are cancellation rates for each of nine sales people during each of 4 years. Use an appropriate test at level .05 to see whether true average cancellation rate depends on the year.

A random sample of 15 automobile mechanics certified to work on a certain type of car was selected, and the time (in minutes) necessary for each one to diagnose a particular problem was determined, resulting in the following data:

30.6 30.1 15.6 26.7 27.1 25.4 35.0 30.8

31.6 53.2 12.5 23.2 8.8 24.9 30.2

Use the Wilcoxon test at significance level .10 to decide whether the data suggests that true average diagnostic time is less than 30 minutes.

Suppose we wish to test.

: the X and Y distributions are identical

versus

: the X distribution is less spread out than the Y

distribution

The accompanying figure pictures X and Y distributions for which is true. The Wilcoxon rank-sum test is not appropriate in this situation because when is true as pictured, the Y鈥檚 will tend to be at the extreme ends of the combined sample (resulting in small and large Y ranks), so the sum of X ranks will result in a W value that is neither large nor small.

Consider modifying the procedure for assigning ranks as follows: After the combined sample of m + n observations is ordered, the smallest observation is given rank 1, the largest observation is given rank 2, the second smallest is

given rank 3, the second largest is given rank 4, and so on. Then if is true as pictured, the X values will tend to be in the middle of the sample and thus receive large ranks. Let W鈥 denote the sum of the X ranks and consider an uppertailed test based on this test statistic. When is true, every possible set of X ranks has the same probability, so W鈥 has the same distribution as does W when H0 is true. The accompanying data refers to medial muscle thickness for arterioles from the lungs of children who died from sudden infant death syndrome (x鈥檚) and a control group of children (y鈥檚). Carry out the test of versus at level .05.

SIDS 4.0 4.4 4.8 4.9

Control 3.7 4.1 4.3 5.1 5.6

Consult the Lehmann book (in the chapter bibliography) for more information on this test, called the Siegel-Tukey test.

The study reported in 鈥淕ait Patterns During Free Choice Ladder Ascents鈥 (Human Movement Sci., 1983: 187鈥195) was motivated by publicity concerning the increased accident rate for individuals climbing ladders. A number of different gait patterns were used by subjects climbing a portable straight ladder according to specified instructions. The ascent times for seven subjects who used a lateral gait and six subjects who used a four-beat diagonal gait are given.

Lateral 0.86 1.31 1.64 1.51 1.53 1.39 1.09

Diagonal 1.27 1.82 1.66 0.85 1.45 1.24

a. Carry out a test using a 5 .05 to see whether the data suggests any difference in the true average ascent times for the two gaits.

b. Compute a 95% CI for the difference between the true average gait times.

The urinary fluoride concentration (parts per million) was measured both for a sample of livestock grazing in an area previously exposed to fluoride pollution and for a similar sample grazing in an unpolluted region:

Polluted

\(21.3\)

\(18.7\)

\(23.0\)

\(17.1\)

\(16.8\)

\(20.9\)

\(19.7\)

Unpolluted

\(14.2\)

\(18.3\)

\(17.2\)

\(18.4\)

\(20.0\)



Does the data indicate strongly that the true average fluoride concentration for livestock grazing in the polluted region is larger than for the unpolluted region? Use the Wilcoxon rank-sum test at level\(\alpha = .01\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.