/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 Use the following information to... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use the following information to answer the next 14 exercises: The mean age for all Foothill College students for a recent Fall term was 33.2. The population standard deviation has been pretty consistent at 15. Suppose that twenty-five Winter students were randomly selected. The mean age for the sample was 30.4. We are interested in the true mean age for Winter Foothill College students. Let X = the age of a Winter Foothill College student. As a result of your answer to Exercise 8.26, state the exact distribution to use when calculating the confidence interval.

Short Answer

Expert verified
Use the standard normal (Z) distribution to calculate the confidence interval.

Step by step solution

01

Identify Parameters

The problem provides the population mean \(\mu = 33.2\) and the population standard deviation \(\sigma = 15\). The sample mean \(\bar{x} = 30.4\) and the sample size is \(n = 25\).
02

Determine Distribution Characteristics

Since the population standard deviation is known and the sample size \(n=25\) is relatively small, we would generally use a normal distribution to handle this problem. However, the central limit theorem allows us to use the normal distribution when the sample size is not extremely small (usually \(n \geq 30\) is ideal), but here it is typically accepted for context like this when \(n\) is at least 25 and the population standard deviation is known.
03

State the Appropriate Distribution

For calculating the confidence interval in this context, given that the population standard deviation is known, we utilize the standard normal (Z) distribution. Ensure the assumptions are satisfied based on the Central Limit Theorem when making this choice.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Central Limit Theorem
The Central Limit Theorem (CLT) is a fundamental concept in statistics. It states that, as a sample size becomes large, the distribution of the sample mean will approach a normal distribution. This is true even if the population from which the sample is drawn is not normally distributed. This theorem is highly useful because it allows us to make inferences about population parameters using sample statistics.
In practical terms, the CLT provides the assurance that in cases where the sample size is large enough (typically, at least 30 is ideal), we can apply normal distribution to the sample mean. This simplifies calculations significantly, especially for constructing confidence intervals and hypothesis testing.
In the context of our exercise, because the sample size of 25 is close to 30, the CLT allows us to assume the sample mean follows a normal distribution even if the original data does not. This makes our calculations for confidence intervals more straightforward.
Population Standard Deviation
The population standard deviation (c) is a measure of the amount of variation or dispersion within a set of data points in the entire population. Simply put, it shows how much the individual data points differ from the population mean. Knowing the population standard deviation is crucial for certain statistical analyses.
  • It is particularly important when determining the distribution to use in various statistical calculations. For example, when the population standard deviation is known, the normal distribution can be applied.
  • In our exercise, we know that c = 15, and this known value allows us to use the Z-distribution rather than the t-distribution when calculating confidence intervals.
  • Having the population standard deviation takes some complexities out of statistical analysis since you can apply straightforward formulas for confidence intervals and other estimates.
Knowing the population's variability aids in making precise predictions about which statistical methods to apply.
Sample Mean
The sample mean (c04) is an important statistical measure that represents the average of a sample from the population. It serves as an estimate of the population mean (bc). The reliability of the sample mean increases with the size of the sample.
  • The sample mean is calculated by summing all sample observations and dividing by the sample size (c3). In our scenario, the sample mean is given as 30.4.
  • One of its main uses is to estimate population parameters. The sample mean provides a point estimate for the population mean, which means we use c04 to assess what bc might be.
  • Sample mean variability is affected by sample size. Larger samples tend to result in a sample mean closer to the population mean, reducing estimation error.
This concept is vital because it forms the basis for statistical inference, such as estimating confidence intervals or testing hypotheses.
Normal Distribution
Normal distribution is a common continuous probability distribution characterized by its bell-shaped curve, being symmetric about the mean. When data follows a normal distribution, most data points cluster around the mean and fewer farther away, making it an essential model in statistics.
Key properties of normal distribution include:
  • The mean, median, and mode are all equal.
  • The distribution is perfectly symmetric about the mean.
  • The shape of the curve is defined by the mean (bc) and the standard deviation (c). A larger standard deviation results in a wider spread.
In statistical practice, many tests assume normality. Although real-world data might not perfectly follow the normal distribution, for many practical purposes, it serves as an excellent approximation.
In the provided exercise, the normal distribution is used to create a confidence interval because we have knowledge of the population standard deviation and a sufficiently large sample, aligning with the requirements of the Central Limit Theorem.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use the following information to answer the next 16 exercises: The Ice Chalet offers dozens of different beginning ice-skating classes. All of the class names are put into a bucket. The 5 P.M., Monday night, ages 8 to 12, beginning ice-skating class was picked. In that class were 64 girls and 16 boys. Suppose that we are interested in the true proportion of girls, ages 8 to 12, in all beginning ice-skating classes at the Ice Chalet. Assume that the children in the selected class are a random sample of the population. Define a new random variable \(P^{\prime} .\) What is \(p^{\prime}\) estimating?

Use the following information to answer the next six exercises: One hundred eight Americans were surveyed to determine the number of hours they spend watching television each month. It was revealed that they watched an average of 151 hours each month with a standard deviation of 32 hours. Assume that the underlying population distribution is normal. Construct a 99% confidence interval for the population mean hours spent watching television per month. (a) State the confidence interval, (b) sketch the graph, and (c) calculate the error bound.

Use the following information to answer the next ten exercises: A sample of 20 heads of lettuce was selected. Assume that the population distribution of head weight is normal. The weight of each head of lettuce was then recorded. The mean weight was 2.2 pounds with a standard deviation of 0.1 pounds. The population standard deviation is known to be 0.2 pounds. In words, define the random variable \(X .\)

Use the following information to answer the next 14 exercises: The mean age for all Foothill College students for a recent Fall term was 33.2. The population standard deviation has been pretty consistent at 15. Suppose that twenty-five Winter students were randomly selected. The mean age for the sample was 30.4. We are interested in the true mean age for Winter Foothill College students. Let X = the age of a Winter Foothill College student. Is \(\sigma_{x}\) known?

Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its mean number of unoccupied seats per flight over the past year. To accomplish this, the records of 225 flights are randomly selected and the number of unoccupied seats is noted for each of the sampled flights. The sample mean is 11.6 seats and the sample standard deviation is 4.1 seats. a. i. \(\overline{x}=\) _____ ii. \(s_{x}=\) _____ iii. \(n=\) _____ iv. \(n-1=\) _____ b. Define the random variables \(X\) and \(\overline{X}\) in words. c. Which distribution should you use for this problem? Explain your choice. d. Construct a 92\(\%\) confidence interval for the population mean number of unoccupied seats per flight. i. State the confidence interval. ii. Sketch the graph. iii. Calculate the error bound.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.