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Use the following information to answer the next 14 exercises: The mean age for all Foothill College students for a recent Fall term was 33.2. The population standard deviation has been pretty consistent at 15. Suppose that twenty-five Winter students were randomly selected. The mean age for the sample was 30.4. We are interested in the true mean age for Winter Foothill College students. Let X = the age of a Winter Foothill College student. Is \(\sigma_{x}\) known?

Short Answer

Expert verified
Yes, the population standard deviation \( \sigma \) is known.

Step by step solution

01

Identify Given Values

The given information includes the mean age for all Foothill College students, which is 33.2, and the standard deviation of the population, which is 15. From this, we know that the standard deviation of the population \( \sigma \) is known. We also have a sample of twenty-five students with a sample mean age of 30.4.
02

Determine Population Standard Deviation

The population standard deviation \( \sigma \) is explicitly given as 15. This is an important piece of information because it affects whether we use a standard normal distribution (Z-distribution) or a t-distribution for further statistical calculations.
03

Confirm Known \( \sigma_x \)

Since \( \sigma \) (the population standard deviation) is known and equals 15, \( \sigma_x \), which refers to the standard deviation of the mean of the sample, is also known. \( \sigma_x \) is calculated using the formula for the standard error of the mean, which is \( \sigma_x = \frac{\sigma}{\sqrt{n}} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Mean Age
The term "mean age" refers to the average age of a group of individuals. It is calculated by adding up all the ages in the group and dividing by the number of individuals. In the context of our problem, the mean age for all Foothill College students was given as 33.2 years.

Why is this number important? Because the mean age acts as a central point, providing a snapshot of the age distribution of the student body. When we want to compare another group's mean age, such as the Winter students' ages, this number serves as a baseline.

By knowing the overall mean age, researchers can identify trends or deviations in specific subgroups, which can be crucial for policy-making or understanding student demographics.
Sample Mean and its Importance
The sample mean is a useful tool in statistics. It represents the average of a smaller group selected from a larger population. In real-life scenarios, collecting data for an entire population can be impractical due to time and resource constraints. Therefore, sampling comes in handy.

Here, the sample mean age refers to the average age of the twenty-five randomly selected Winter students, which was 30.4 years. By comparing this to the overall mean age of 33.2, we can infer certain things about the seasonal differences in the student body.

However, remember that a sample mean is just an estimate of the population mean. This means it's subject to sampling variability. In other words, different samples might have slightly varied mean ages. Hence, it provides a way to estimate the population parameters, although it's not the final word.
Understanding Standard Error
Standard error is a statistical concept that measures the accuracy with which a sample represents a population. It basically reflects how much the sample mean would likely fluctuate from sample to sample.

We determine the standard error of the mean, denoted as \( \sigma_x \), using the formula: \( \sigma_x = \frac{\sigma}{\sqrt{n}} \), where \( \sigma \) is the population standard deviation and \( n \) is the sample size.

In the case presented, the population standard deviation \( \sigma \) is 15, and our sample size \( n \) is 25. Substituting these values into the formula gives us the standard error, which helps us understand how close the sample mean of 30.4 might be to the true mean age of all Winter students.
  • This calculated standard error allows researchers to make more accurate predictions and gives insights into the reliability of the sample mean as a representative of the population mean.
By understanding the standard error, we gain insight into the precision of our statistical estimates.

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Most popular questions from this chapter

The average height of young adult males has a normal distribution with standard deviation of 2.5 inches. You want to estimate the mean height of students at your college or university to within one inch with 93% confidence. How many male students must you measure?

Use the following information to answer the next two exercises: A quality control specialist for a restaurant chain takes a random sample of size 12 to check the amount of soda served in the 16 oz. serving size. The sample mean is 13.30 with a sample standard deviation of 1.55. Assume the underlying population is normally distributed. Find the 95\(\%\) Confidence Interval for the true population mean for the amount of soda served. a. \((12.42,14.18)\) b. \((12.32,14.29)\) C. \((12.50,14.10)\) d. Impossible to determine

Use the following information to answer the next six exercises: One hundred eight Americans were surveyed to determine the number of hours they spend watching television each month. It was revealed that they watched an average of 151 hours each month with a standard deviation of 32 hours. Assume that the underlying population distribution is normal. Why would the error bound change if the confidence level were lowered to 95%?

Use the following information to answer the next 14 exercises: The mean age for all Foothill College students for a recent Fall term was 33.2. The population standard deviation has been pretty consistent at 15. Suppose that twenty-five Winter students were randomly selected. The mean age for the sample was 30.4. We are interested in the true mean age for Winter Foothill College students. Let X = the age of a Winter Foothill College student. What is \(\overline{x}\) estimating?

Use the following information to answer the next five exercises. Suppose the marketing company did do a survey. They randomly surveyed 200 households and found that in 120 of them, the woman made the majority of the purchasing decisions. We are interested in the population of households where women make the majority of the purchasing decisions. Identify the following: a. \(x=\) _____ b. \(n=\) ______ c. \(p^{\prime}=\) _____

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