/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 83 Use the following information to... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use the following information to answer the next 16 exercises: The Ice Chalet offers dozens of different beginning ice-skating classes. All of the class names are put into a bucket. The 5 P.M., Monday night, ages 8 to 12, beginning ice-skating class was picked. In that class were 64 girls and 16 boys. Suppose that we are interested in the true proportion of girls, ages 8 to 12, in all beginning ice-skating classes at the Ice Chalet. Assume that the children in the selected class are a random sample of the population. Define a new random variable \(P^{\prime} .\) What is \(p^{\prime}\) estimating?

Short Answer

Expert verified
The random variable \( P^\prime \) estimates the proportion of girls in the class, which is 0.8.

Step by step solution

01

Understand the Random Variable

The random variable \( P^\prime \) represents the sample proportion. In this context, it denotes the proportion of girls in the selected ice-skating class.
02

Calculate the Sample Proportion

To estimate the sample proportion \( p^\prime \), we divide the number of girls by the total number of students in the class. There are 64 girls and 16 boys, making a total of 80 students. Thus, \( p^\prime = \frac{64}{80} \).
03

Simplify the Fraction

Simplify the fraction \( \frac{64}{80} \) to its lowest terms. Divide both the numerator and the denominator by their greatest common divisor, which is 16, giving \( \frac{4}{5} \).
04

Interpret the Estimate

The value \( p^\prime = \frac{4}{5} \) or 0.8 estimates the proportion of girls in all beginning ice-skating classes at the Ice Chalet.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Variable
A random variable is a fundamental concept in statistics and probability. It is essentially a variable that can take on different values, each associated with a probability. In our exercise, the random variable is represented by \( P' \), which signifies the sample proportion of girls in the ice-skating class. Random variables help us to make sense of variability in data.
Understanding random variables is crucial because they allow statisticians to quantify uncertainty and variability in their analyses. In practical terms, \( P' \) is the outcome of randomly selecting a class from the Ice Chalet and calculating the proportion of girls present. The concept of randomness introduces an element of chance, as different samples may yield different proportions of girls.
When dealing with random variables, it is important to remember that they are not deterministic. Instead, they provide a bridge between theoretical probability distributions and real-world data through the lens of randomness.
Proportion Estimation
Proportion estimation is the process of using sample data to estimate a population proportion. In our example, we want to estimate the true proportion of girls aged 8 to 12 in all beginning ice-skating classes at the Ice Chalet. The sample proportion \( p' \) is an unbiased estimator of the true population proportion.
To calculate the sample proportion, you divide the number of desired outcomes by the total number of outcomes. For instance, the sample proportion of girls in this class is \( \frac{64}{80} \), which simplifies to \( \frac{4}{5} \) or 0.8.
Estimating proportions is valuable because it allows you to make inferences about a whole population from a fraction of that population. However, always remember that the accuracy of your estimate depends on the randomness and size of your sample.
Statistical Sampling
Statistical sampling is a technique in statistics where a subset of individuals is selected from a larger population to gather insights and make inferences about that population. In the context of our problem, the selected ice-skating class is considered a sample of the larger population of all classes at the Ice Chalet.
The key to successful inference from a sample is ensuring that the sample is random. A random sample is one in which each member of the population has an equal chance of being selected. This randomness helps to ensure that the sample is representative of the population, minimizing bias.
Moreover, statistical sampling is essential for practical reasons. It is often impractical or impossible to collect data from an entire population due to constraints like time, cost, or feasibility. Sampling allows researchers to draw meaningful conclusions with limited resources. However, it's important to ensure that sample size and randomness are adequate to ensure reliable and valid estimates.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use the following information to answer the next 13 exercises: The data in Table 8.10 are the result of a random survey of 39 national flags (with replacement between picks) from various countries. We are interested in finding a confidence interval for the true mean number of colors on a national flag. Let X = the number of colors on a national flag. $$\begin{array}{|c|c|}\hline X & {\text { Freq }} \\ \hline 1 & {1} \\\ \hline 2 & {7} \\ \hline 3 & {78} \\ \hline 4 & {7} \\ \hline 5 & {6} \\\ \hline\end{array}$$ What is \(\overline{x}\) estimating?

Construct a 95\(\%\) Confidence Interval for the true mean age of winter Foothill College students by working out then answering the next seven exercises. Using the same mean, standard deviation, and sample size, how would the error bound change if the confidence level were reduced to 90%? Why?

Use the following information to answer the next five exercises. Suppose the marketing company did do a survey. They randomly surveyed 200 households and found that in 120 of them, the woman made the majority of the purchasing decisions. We are interested in the population of households where women make the majority of the purchasing decisions. Define the random variables \(X\) and \(P^{\prime}\) in words.

Use the following information to answer the next 14 exercises: The mean age for all Foothill College students for a recent Fall term was 33.2. The population standard deviation has been pretty consistent at 15. Suppose that twenty-five Winter students were randomly selected. The mean age for the sample was 30.4. We are interested in the true mean age for Winter Foothill College students. Let X = the age of a Winter Foothill College student. \(n=\)

Use the following information to answer the next 14 exercises: The mean age for all Foothill College students for a recent Fall term was 33.2. The population standard deviation has been pretty consistent at 15. Suppose that twenty-five Winter students were randomly selected. The mean age for the sample was 30.4. We are interested in the true mean age for Winter Foothill College students. Let X = the age of a Winter Foothill College student. As a result of your answer to Exercise 8.26, state the exact distribution to use when calculating the confidence interval.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.