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Use the following information to answer the next five exercises. Suppose the marketing company did do a survey. They randomly surveyed 200 households and found that in 120 of them, the woman made the majority of the purchasing decisions. We are interested in the population of households where women make the majority of the purchasing decisions. Define the random variables \(X\) and \(P^{\prime}\) in words.

Short Answer

Expert verified
\(X\) is the number of households (out of 200) where women make most decisions; \(P^{\prime}\) is the sample proportion, \(\frac{X}{200}\).

Step by step solution

01

Understand Random Variables

Random variables are used in statistics to denote numerical outcomes of random phenomena. In this case, we have surveys as our random phenomena.
02

Define the Random Variable X

The random variable \(X\) represents the number of households out of 200 surveyed, in which women make the majority of purchasing decisions. In this context, \(X\) can be any integer from 0 to 200.
03

Define the Sample Proportion P'

The sample proportion \(P^{\prime}\) is defined as the proportion of households in the sample where women make the majority of the purchasing decisions. This is computed by dividing \(X\) by the total number of households surveyed, i.e., \( \frac{X}{200} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Variables
A random variable is a fundamental concept in statistics used to quantify outcomes from random events or processes. In our scenario, the random event is the survey conducted among households. The goal of defining a random variable is to translate the outcome of a survey question into a numerical format that can be analyzed.

For this survey, we consider households as our units of observation. Each household has a potential outcome of either the woman making the majority of purchasing decisions, or not. The exercise introduces the random variable \(X\). Here, \(X\) represents the count of households (out of 200 surveyed) where women make the majority of purchasing decisions.

In a practical sense, the possible values for \(X\) span from 0 to 200 because it is conceivable that anywhere from none to all surveyed households could fall into this category. By using random variables such as \(X\), statisticians can work through calculations and predictions using numerical methods.
Sample Proportion
Sample proportion is the ratio of occurrences of a particular outcome to the total sample size, providing insights into how frequently a certain characteristic appears. In our case, the sample proportion \(P^{\prime}\) represents the fraction of surveyed households where women make the majority of purchasing decisions. This metric helps to summarize the survey results succinctly.

To calculate \(P^{\prime}\), we take the random variable \(X\), which tells us how many households in the sample fit our criteria, and divide it by the total number of surveyed households. Mathematically this is expressed as:\[P^{\prime} = \frac{X}{200}\] If we use the given numbers, where \(X = 120\), the calculation would be:\[P^{\prime} = \frac{120}{200} = 0.6\]
This result means that, according to our sample, 60% of households have women making the majority of purchasing decisions. Sample proportions are particularly useful as they provide a quick snapshot of data, which can be expanded to infer about larger populations.
Survey Analysis
Survey analysis involves collecting, examining, and interpreting data from surveys to make informed decisions. Surveys are valuable tools in research for capturing data regarding behaviors, preferences, and characteristics, as seen in our example.

Analyzing the survey starts with defining the goal; here, it is to determine which households have women making most purchasing decisions. After conducting the survey, the next step is data cleaning and organizing. This involves checking for completeness and accuracy.

Calculations like determining the sample proportion \(P^{\prime}\) help summarize findings and create a foundational understanding. Once the initial data is prepped, researchers often look for patterns or deviations that can provide deeper insights. Finally, comparing survey results to existing benchmarks or prior data can highlight trends or changes in behavior.

By following these steps, survey analysis not only clarifies current scenarios but also aids in making data-driven forecasts and recommendations for policy or business strategies.

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Most popular questions from this chapter

Use the following information to answer the next 16 exercises: The Ice Chalet offers dozens of different beginning ice-skating classes. All of the class names are put into a bucket. The 5 P.M., Monday night, ages 8 to 12, beginning ice-skating class was picked. In that class were 64 girls and 16 boys. Suppose that we are interested in the true proportion of girls, ages 8 to 12, in all beginning ice-skating classes at the Ice Chalet. Assume that the children in the selected class are a random sample of the population. State the estimated distribution of \(X . X \sim\) _____

Use the following information to answer the next two exercises: A quality control specialist for a restaurant chain takes a random sample of size 12 to check the amount of soda served in the 16 oz. serving size. The sample mean is 13.30 with a sample standard deviation of 1.55. Assume the underlying population is normally distributed. Find the 95\(\%\) Confidence Interval for the true population mean for the amount of soda served. a. \((12.42,14.18)\) b. \((12.32,14.29)\) C. \((12.50,14.10)\) d. Impossible to determine

Use the following information to answer the next six exercises: One hundred eight Americans were surveyed to determine the number of hours they spend watching television each month. It was revealed that they watched an average of 151 hours each month with a standard deviation of 32 hours. Assume that the underlying population distribution is normal. Why would the error bound change if the confidence level were lowered to 95%?

Use the following information to answer the next five exercises. A hospital is trying to cut down on emergency room wait times. It is interested in the amount of time patients must wait before being called back to be examined. An investigation committee randomly surveyed 70 patients. The sample mean was 1.5 hours with a sample standard deviation of 0.5 hours. Identify the following: a. \(x=\) b. \(s_{x}=\) C. \(n=\) d. \(n-1=\)

Use the following information to answer the next 16 exercises: The Ice Chalet offers dozens of different beginning ice-skating classes. All of the class names are put into a bucket. The 5 P.M., Monday night, ages 8 to 12, beginning ice-skating class was picked. In that class were 64 girls and 16 boys. Suppose that we are interested in the true proportion of girls, ages 8 to 12, in all beginning ice-skating classes at the Ice Chalet. Assume that the children in the selected class are a random sample of the population. Using the same \(p^{\prime}\) and \(n=80,\) how would the error bound change if the confidence level were increased to 98\(\% ?\) Why?

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