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Complete the expected value table. $$\begin{array}{|l|l|}\hline x & {P(x)} & {x^{*} P(x)} \\ \hline 0 & {0.2} \\\ \hline 1 & {0.2} \\ \hline 2 & {0.4} \\ \hline 3 & {0.2} \\\ \hline\end{array}$$

Short Answer

Expert verified
The expected value table is now complete with: \(x^*P(x)\) values of 0, 0.2, 0.8, and 0.6 corresponding to \(x\) values 0, 1, 2, and 3, respectively.

Step by step solution

01

Understand the Table

The table provides different values of a random variable \(x\), along with their corresponding probabilities \(P(x)\). Our task is to complete the table by calculating the product of each value \(x\) and its probability \(P(x)\) to fill the third column \(x^* P(x)\).
02

Calculate for \(x = 0\)

For \(x = 0\), we find the product of \(x\) and \(P(x)\): \[ x^* P(x) = 0 * 0.2 = 0 \] Thus, the entry for \(x^* P(x)\) at \(x = 0\) is 0.
03

Calculate for \(x = 1\)

For \(x = 1\), calculate as follows: \[ x^* P(x) = 1 * 0.2 = 0.2 \] Therefore, the entry for \(x^* P(x)\) at \(x = 1\) is 0.2.
04

Calculate for \(x = 2\)

For \(x = 2\), proceed with the calculation: \[ x^* P(x) = 2 * 0.4 = 0.8 \] So, the entry for \(x^* P(x)\) at \(x = 2\) is 0.8.
05

Calculate for \(x = 3\)

For \(x = 3\), compute: \[ x^* P(x) = 3 * 0.2 = 0.6 \] Thus, the entry for \(x^* P(x)\) at \(x = 3\) is 0.6.
06

Verify Table Completeness

We have completed the third column by calculating each \(x^* P(x)\). The full table with calculations is:\[\begin{array}{|c|c|c|}\hlinex & P(x) & x^* P(x) \\hline0 & 0.2 & 0 \1 & 0.2 & 0.2 \2 & 0.4 & 0.8 \3 & 0.2 & 0.6 \\hline\end{array}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Distribution
A probability distribution is a list or a table that shows all the possible values of a random variable and the likelihood, or probability, that each value will occur. In our example, the random variable \( x \) can take on the values 0, 1, 2, and 3. Each of these values has an associated probability \( P(x) \) which tells us how likely that specific outcome is. For example, the chance that \( x \) is 2 is known to be 0.4, or 40%.
Understanding probability distributions is crucial because they allow us to predict the likelihood of different outcomes in random events. By organizing these probabilities in a table, we can perform further statistical calculations, like finding the expected value or variance. Remember, all probabilities in a distribution must add up to 1, because one of the possible outcomes must occur. In this case, \( 0.2 + 0.2 + 0.4 + 0.2 = 1.0 \).
When reading a probability distribution table, note how probabilities reflect the chance of observing each outcome. This is instrumental in making predictions and informed decisions in real-life situations or statistical analyses.
Random Variable
A random variable is a numerical outcome of a random process or experiment. It represents possible values from a random event along with accompanying probabilities from a probability distribution. In our exercise, \( x \) is the random variable representing different outcomes based on the context of the problem or experiment that is not specified. For instance, \( x = 0 \) could mean 0 successes in a series of trials, whereas \( x = 3 \) might mean 3 successes.
Random variables can be either discrete or continuous. Discrete random variables, like our \( x \), have distinct, separate values, such as 0, 1, 2, or 3. Meanwhile, continuous random variables can take any value within a specified range. It's important to realize that random variables themselves are not random; their outcomes or values are determined by underlying randomness.
This concept is key in probability and statistics as it helps us model and analyze real-world situations quantitatively. Knowing how to handle random variables enables interpretations of complex systems in fields like finance, engineering, and social sciences.
Probability Calculation
Probability calculation is the process we perform to determine the probability of a particular outcome of a random variable. In this exercise, we used a specific type of probability calculation known as the expected value. It involves multiplying each outcome by its probability and summing these products.
To complete our table, we calculated \( x^* P(x) \) for each value of \( x \):
  • For \( x = 0 \), \( x^* P(x) = 0 \times 0.2 = 0 \)
  • For \( x = 1 \), \( x^* P(x) = 1 \times 0.2 = 0.2 \)
  • For \( x = 2 \), \( x^* P(x) = 2 \times 0.4 = 0.8 \)
  • For \( x = 3 \), \( x^* P(x) = 3 \times 0.2 = 0.6 \)
These calculations help us understand the average or expected value of \( x \) over many trials. The expected value gives a sense of the 'center' of a probability distribution and is a single summary measure that can describe a random variable's likely behavior over time. Thus, probability calculations are foundational in predicting and interpreting random phenomena.

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Most popular questions from this chapter

A venture capitalist, willing to invest \(\$ 1,000,000\), has three investments to choose from. The first investment, a software company, has a 10% chance of returning \(\$ 5,000,000\) profit, a 30% chance of returning \(\$ 1,000,000\) profit, and a 60% chance of losing the million dollars. The second company, a hardware company, has a 20% chance of returning \(\$ 3,000,000\) profit, a 40% chance of returning \(\$ 1,000,000\) profit, and a 40% chance of losing the million dollars. The third company, a biotech firm, has a 10% chance of returning \(\$ 6,000,000\) profit, a 70% of no profit or loss, and a 20% chance of losing the million dollars. a. Construct a PDF for each investment. b. Find the expected value for each investment. c. Which is the safest investment? Why do you think so? d. Which is the riskiest investment? Why do you think so? e. Which investment has the highest expected return, on average?

Use the following information to answer the next eight exercises: The Higher Education Research Institute at UCLA collected data from 203,967 incoming first-time, full-time freshmen from 270 four year colleges and universities in the U.S. 71.3% of those students replied that, yes, they believe that same-sex couples should have the right to legal marital status. Suppose that you randomly pick eight first-time, full-time freshmen from the survey. You are interested in the number that believes that same sex-couples should have the right to legal marital status. On average \((\mu),\) how many would you expect to answer yes?

Use the following information to answer the next eight exercises: The Higher Education Research Institute at UCLA collected data from 203,967 incoming first-time, full-time freshmen from 270 four year colleges and universities in the U.S. 71.3% of those students replied that, yes, they believe that same-sex couples should have the right to legal marital status. Suppose that you randomly pick eight first-time, full-time freshmen from the survey. You are interested in the number that believes that same sex-couples should have the right to legal marital status. Construct the probability distribution function (PDF). $$\begin{array}{|c|c|}\hline x & {P(x)} \\ \hline \\ \hline {} \\ \hline \\\ \hline \\ \hline {} \\ \hline \\ \hline {} \\ \hline \\ \hline \\\ \hline\end{array}$$

Identify the mistake in the probability distribution table. $$\begin{array}{|c|c|c|}\hline x & {P(x)} & {x^{\star} P(x)} \\ \hline 1 & {0.15} & {0.15} \\ \hline 2 & {0.25} & {0.50} \\ \hline 3 & {0.30} & {0.90} \\\ \hline 4 & {0.20} & {0.80} \\ \hline 5 & {0.15} & {0.75} \\\ \hline\end{array}$$

According to a recent article the average number of babies born with significant hearing loss (deafness) is approximately two per 1,000 babies in a healthy baby nursery. The number climbs to an average of 30 per 1,000 babies in an intensive care nursery. Suppose that 1,000 babies from healthy baby nurseries were randomly surveyed. Find the probability that exactly two babies were born deaf.

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