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Use the following information to answer the next five exercises: Javier volunteers in community events each month. He does not do more than five events in a month. He attends exactly five events 35% of the time, four events 25% of the time, three events 20% of the time, two events 10% of the time, one event 5% of the time, and no events 5% of the time. Find the probability that Javier volunteers for at least one event each month. \(P(x>0)=\)________

Short Answer

Expert verified
The probability that Javier volunteers for at least one event is 0.95.

Step by step solution

01

Understand the Problem

We need to find the probability that Javier volunteers for at least one event each month. This can be expressed as the probability that Javier attends more than zero events.
02

Identify Given Probabilities

Javier attends 5 events with a probability of 35%, 4 events with 25%, 3 events with 20%, 2 events with 10%, 1 event with 5%, and 0 events with 5%.
03

Calculate Unwanted Probability

The probability that Javier attends zero events is 5%, or in decimal form: \( P(x = 0) = 0.05 \).
04

Use Complement Rule

The probability that Javier volunteers for at least one event is the complement of him attending zero events. Therefore, \( P(x > 0) = 1 - P(x = 0) \).
05

Calculate Desired Probability

Substitute the given probability into the complement equation: \( P(x > 0) = 1 - 0.05 = 0.95 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complement Rule
The Complement Rule is a fundamental concept in probability theory that helps us find the likelihood of an event by considering the opposite situation. In simple terms, it states that the probability of an event happening and the probability of it not happening will always add up to 1. This is because together, these two scenarios encompass all possible outcomes.

When applying the complement rule, especially in practical situations like event attendance, we often calculate the probability of what we do not want to occur, as this can sometimes be more straightforward. Once we have this, we can simply subtract it from 1 to find the desired probability. In Javier's situation, we needed to find the probability he attends at least one event. However, rather than directly calculate each scenario where he attends events, we recognized it would be easier to find the probability of the complement—Javier attending zero events. After that, using the rule, we determined that the probability of him attending at least one event is:
  • Probability of zero events: 0.05
  • Probability of at least one event: 1 - 0.05 = 0.95
This is how the complement rule simplifies such probability questions.
Probability Distribution
A probability distribution is a comprehensive framework that outlines the likelihood of every outcome in a statistical experiment. In other words, it shows us how probabilities are spread across different potential events. For any discrete random variable, like the number of events Javier attends, this distribution assigns a probability to each possible outcome.

In the example of Javier, the probability distribution would be represented by a list of probabilities associated with him attending 0, 1, 2, 3, 4, or 5 events per month. These probabilities are:
  • 0 events: 5%
  • 1 event: 5%
  • 2 events: 10%
  • 3 events: 20%
  • 4 events: 25%
  • 5 events: 35%
The sum of these probabilities equals 100%, affirming that they represent all possible scenarios. Analyzing this distribution helps in understanding how often each number of events occurs and serves as a foundational tool for calculating different probability-based queries.
Event Attendance
Event attendance probability is a practical application of probability distribution often explored in real-world situations. It involves estimating how likely a person or a group is to attend certain events over a defined period. In Javier's case, we track the frequency of his volunteering activities, using data to gauge the probability of different attendance levels each month.

Some key points to understand about event attendance include:
  • It provides insights into patterns or trends in participation.
  • Understanding attendance distribution helps in planning and resource allocation for community events.
  • It uses probabilities to predict future behavior based on past occurrences.
By analyzing these probabilities, Javier and event organizers can make informed decisions about upcoming events, ensuring that there are adequate resources and plans in place for varying levels of participation.

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Most popular questions from this chapter

Use the following information to answer the next two exercises: The probability that the San Jose Sharks will win any given game is 0.3694 based on a 13-year win history of 382 wins out of 1,034 games played (as of a certain date). An upcoming monthly schedule contains 12 games. The chance of an IRS audit for a tax return with over \(\$ 25,000\) in income is about 2% per year. We are interested in the expected number of audits a person with that income has in a 20-year period. Assume each year is independent. a. In words, define the random variable \( X\). b. List the values that \(X\) may take on. c. Give the distribution of \(X . X \sim\) ___ (___,____) d. How many audits are expected in a 20-year period? e. Find the probability that a person is not audited at all. f. Find the probability that a person is audited more than twice.

Use the following information to answer the next two exercises: The probability that the San Jose Sharks will win any given game is 0.3694 based on a 13-year win history of 382 wins out of 1,034 games played (as of a certain date). An upcoming monthly schedule contains 12 games. The expected number of wins for that upcoming month is: a. 1.67 b. 12 c. \(\frac{382}{1043}\) d. 4.43 Let \(X =\) the number of games won in that upcoming month.

Use the following information to answer the next six exercises: A baker is deciding how many batches of muffins to make to sell in his bakery. He wants to make enough to sell every one and no fewer. Through observation, the baker has established a probability distribution. $$\begin{array}{|c|c|}\hline x & {P(x)} \\ \hline 1 & {0.15} \\ \hline 2 & {0.35} \\ \hline 3 & {0.40} \\ \hline 4 & {0.10} \\ \hline\end{array}$$ What is the probability the baker will sell exactly one batch? \(P(x=1)=\)_________

Use the following information to answer the next six exercises: A baker is deciding how many batches of muffins to make to sell in his bakery. He wants to make enough to sell every one and no fewer. Through observation, the baker has established a probability distribution. $$\begin{array}{|c|c|}\hline x & {P(x)} \\ \hline 1 & {0.15} \\ \hline 2 & {0.35} \\ \hline 3 & {0.40} \\ \hline 4 & {0.10} \\ \hline\end{array}$$ On average, how many batches should the baker make?

Use the following information to answer the next four exercises. Recently, a nurse commented that when a patient calls the medical advice line claiming to have the flu, the chance that he or she truly has the flu (and not just a nasty cold) is only about 4%. Of the next 25 patients calling in claiming to have the flu, we are interested in how many actually have the flu. On average, for every 25 patients calling in, how many do you expect to have the flu?

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