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What is the probability of arriving at a traffic light when it is red if the red signal is lit for \(30 \mathrm{sec}\), the yellow signal for \(5 \mathrm{sec}\), and the green signal for \(45 \mathrm{sec}\) ?

Short Answer

Expert verified
The probability of arriving at a traffic light when it is red is \(\frac{3}{8}\).

Step by step solution

01

Find total duration of one complete cycle

To find the total duration of one cycle, we will sum up the duration of all three signals: red, yellow, and green. Let T be the total duration of the cycle: \[T = 30 sec + 5 sec + 45 sec\]
02

Calculate the probability

Now that we have the total duration of one cycle (T), we can find the probability of arriving at the traffic light when it is red. We know that the red signal is lit for 30 seconds, so we can find the probability by dividing the duration of the red signal by the total duration, T: \[\text{Probability} = \frac{\text{Duration of red signal}}{\text{Total duration}}\]
03

Plug in values and compute

Now we can plug in the values for the duration of the red light and the total duration of the cycle: \[\text{Probability} = \frac{30 sec}{30 sec + 5 sec + 45 sec}\]
04

Simplify the expression

Next, we will simplify the expression by adding the durations: \[\text{Probability} = \frac{30 sec}{80 sec}\]
05

Calculate the final probability

Now, we will simplify the fraction to obtain our final probability: \[\text{Probability} = \frac{3}{8}\] Therefore, the probability of arriving at a traffic light when it is red is \(\frac{3}{8}\).

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