/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 35 In a survey on consumer-spending... [FREE SOLUTION] | 91Ó°ÊÓ

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In a survey on consumer-spending methods conducted in 2006, the following results were obtained: $$\begin{array}{lccccc} \hline & & & & {\text { Debit/ATM }} & \\ \text { Payment Method } & \text { Checks } & \text { Cash } & \text { Credit cards } & \text { cards } & \text { Other } \\ \hline \text { Transactions, \% } & 37 & 14 & 25 & 15 & 9 \\ \hline \end{array}$$ If a transaction tracked in this survey is selected at random, what is the probability that the transaction was paid for a. With a credit card or with a debit/ATM card? b. With cash or some method other than with a check, a credit card, or a debit/ATM card?

Short Answer

Expert verified
a. The probability of the transaction being paid with a credit or debit/ATM card is \(40\%\). b. The probability of the transaction being paid with cash or some other method than check, credit card, or debit/ATM card is \(23\%\).

Step by step solution

01

a. Probability of the transaction paid with a credit card or with a debit/ATM card.

To find this probability, we look at the survey and see the percentage of transactions made by credit cards and debit/ATM cards. Then, we add these percentages together because the events are mutually exclusive. Credit cards: 25% Debit/ATM cards: 15% So the probability of the transaction being paid with a credit or debit/ATM card is = 25% + 15% = 40%.
02

b. Probability of the transaction paid with cash or some method other than a check, a credit card, or a debit/ATM card.

To find this probability, we look at the survey and see the percentage of transactions made by cash and other methods, excluding checks, credit cards, and debit/ATM cards. Then, we add these percentages together because the events are mutually exclusive. Cash: 14% Other methods: 9% So the probability of the transaction being paid with cash or some other method than check, credit card, or debit/ATM card is = 14% + 9% = 23%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mutually Exclusive Events
Understanding the idea of mutually exclusive events is critical when analyzing the probability of outcomes within a given survey. Mutually exclusive events are two or more events that cannot occur at the same time. For instance, when a payment is made, it can only be processed using one method at that moment—either cash, check, credit card, debit/ATM card, or some other method.

In the context of the survey from the 2006 consumer-spending methods, if we're trying to determine the probability of a transaction being paid either with a credit card or with a debit/ATM card, we consider these two payment methods as mutually exclusive events. Why? Because a single transaction cannot be paid with both a credit card and a debit/ATM card at the same time. Thus, to find the combined probability of either event occurring, we simply add their individual probabilities together.

Remember that the concept of mutually exclusive events only applies if there is no overlap between the events. If some transactions were possible with multiple payment methods at the same time, they would not be mutually exclusive, and we would need a different approach to calculate the probability. Mathematically, if two events 'A' and 'B' are mutually exclusive, the probability that either 'A' or 'B' occurs is the sum of their individual probabilities: \( P(A \text{ or } B) = P(A) + P(B) \).
Probability Calculation
Probability calculation allows us to quantify the likelihood of various outcomes. The probability of an event is typically expressed as a fraction or percentage and represents the ratio of the favorable outcomes to the total number of possible outcomes. When dealing with percentages, it's essential to remember that the total probability of all possible exclusive outcomes of an event always sums up to 100%.

Using the consumer-spending methods survey as an illustration, we can calculate the probability for different payment types by converting the given percentages into probabilities. For example, the survey states that 25% of transactions are made using credit cards, which translates to a probability of 0.25 (since percentages are out of 100). The same method applies to debit/ATM card transactions with a 15% or 0.15 probability.

To find the probability of a transaction being made with either a credit or a debit/ATM card, we add the two probabilities together, giving us 0.25 + 0.15 = 0.40, or 40%. This calculation is correct because the events—paying with a credit card or paying with a debit/ATM card—are mutually exclusive.
Survey Data Analysis
Survey data analysis involves interpreting and making conclusions from data collected via surveys. It's a process that helps us understand patterns and preferences within a population. The analysis of such data can often include the calculation of probabilities, as seen in our example with consumer spending methods.

When analyzing survey data, it's essential to categorize the information accurately. There can be a temptation to look at survey percentages and immediately draw conclusions. However, a thorough analysis requires careful consideration of what each percentage represents and the relationships between various categories. For example, in the exercise, we calculated the probability of a transaction being made with cash or other methods. We deliberately excluded methods like checks, credit cards, and debit/ATM cards from this calculation because we were interested only in those transactions that did not use these three methods.

Effective survey data analysis also involves recognizing and interpreting mutually exclusive categories, as it affects how probabilities are computed. By carefully considering each category and its relationships with others, we can ensure accurate, meaningful insights from survey data. Moreover, when faced with complex survey results, breaking down the data into mutually exclusive events can simplify analysis and highlight clearer trends for better decision-making.

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Most popular questions from this chapter

A poll was conducted among 250 residents of a certain city regarding tougher gun-control laws. The results of the poll are shown in the table: $$ \begin{array}{lccccc} \hline & \begin{array}{c} \text { Own } \\ \text { Only a } \\ \text { Handgun } \end{array} & \begin{array}{c} \text { Own } \\ \text { Only a } \\ \text { Rifle } \end{array} & \begin{array}{c} \text { Own a } \\ \text { Handgun } \\ \text { and a Rifle } \end{array} & \begin{array}{c} \text { Own } \\ \text { Neither } \end{array} & \text { Total } \\ \hline \text { Favor } & & & & & \\ \text { Tougher Laws } & 0 & 12 & 0 & 138 & 150 \\ \hline \begin{array}{l} \text { Oppose } \\ \text { Tougher Laws } \end{array} & 58 & 5 & 25 & 0 & 88 \\ \hline \text { No } & & & & & \\ \text { Opinion } & 0 & 0 & 0 & 12 & 12 \\ \hline \text { Total } & 58 & 17 & 25 & 150 & 250 \\ \hline \end{array} $$ If one of the participants in this poll is selected at random, what is the probability that he or she a. Favors tougher gun-control laws? b. Owns a handgun? c. Owns a handgun but not a rifle? d. Favors tougher gun-control laws and does not own a handgun?

Let \(E\) be any cvent in a sample space \(S .\) a. Are \(E\) and \(S\) independent? Explain your answer. b. Are \(E\) and \(\varnothing\) independent? Explain your answer.

In a past presidential election, it was estimated that the probability that the Republican candidate would be elected was \(\frac{3}{5}\), and therefore the probability that the Democratic candidate would be elected was \(\frac{2}{5}\) (the two Independent candidates were given no chance of being elected). It was also estimated that if the Republican candidate were elected, the probability that a conservative, moderate, or liberal judge would be appointed to the Supreme Court (one retirement was expected during the presidential term) was \(\frac{1}{2}, \frac{1}{3}\), and \(\frac{1}{6}\), respectively. If the Democratic candidate were elected, the probabilities that a conservative, moderate, or liberal judge would be appointed to the Supreme Court would be \(\frac{1}{8}, \frac{3}{8}\), and \(\frac{1}{2}\), respectively. A conservative judge was appointed to the Supreme Court during the presidential term. What is the probability that the Democratic candidate was elected?

Suppose the probability that an event will occur in one trial is \(p\). Show that the probability that the event will occur at least once in \(n\) independent trials is \(1-(1-p)^{n}\).

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