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A druggist wishes to select three brands of aspirin to sell in his store. He has five major brands to choose from: \(\mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D}\), and \(\mathrm{E}\). If he selects the three brands at random, what is the probability that he will select a. Brand \(\mathrm{B}\) ? b. Brands \(\mathrm{B}\) and \(\mathrm{C}\) ? c. At least one of the two brands \(\mathrm{B}\) and \(\mathrm{C}\) ?

Short Answer

Expert verified
a. The probability of selecting Brand B is 0.6. b. The probability of selecting Brands B and C is 0.3. c. The probability of selecting at least one of the two brands B and C is 0.9.

Step by step solution

01

Finding total combinations

First, let's find the total number of ways to select three brands from five brands. This can be calculated using the combination formula: \[_nC_r = \frac{n!}{r!(n-r)!}\] where n is the total number of items, and r is the number of items to be chosen. In our case, n = 5 (brands A, B, C, D, E) and r = 3. \[ _5C_3 = \frac{5!}{3! (5-3)!}\]
02

Calculate the combinations

Now, let's calculate the combinations: \[_5C_3 = \frac{5!}{3! 2!} = \frac{120}{12} = 10\] So, there are 10 possible combinations of selecting three brands out of five. Now, we can use these combinations to answer each part of the exercise. #a. Brand B#
03

Count the combinations with Brand B

We need to find the combinations including Brand B. As one brand is already fixed (Brand B), we now need to select two more brands from the remaining four brands (A, C, D, and E). So, we have: \[_4C_2 = \frac{4!}{2!2!} = 6\] So, there are 6 combinations including Brand B.
04

Calculate the probability

Now, let's calculate the probability of selecting Brand B: \[P(B) = \frac{\textrm{Number of combinations with Brand B}}{\textrm{Total combinations}}\] \[P(B) = \frac{6}{10} = 0.6\] The probability of selecting Brand B is 0.6. #b. Brands B and C#
05

Count the combinations with Brands B and C

We need to find the combinations including Brands B and C. As two brands are already fixed (Brand B and Brand C), we now need to select one more brand from the remaining three brands (A, D, and E). So, we have: \[_3C_1 = \frac{3!}{1!2!} = 3\] So, there are 3 combinations including Brands B and C.
06

Calculate the probability

Now, let's calculate the probability of selecting Brands B and C: \[P(B \textrm{ and } C) = \frac{\textrm{Number of combinations with Brands B and C}}{\textrm{Total combinations}}\] \[P(B \textrm{ and } C) = \frac{3}{10} = 0.3\] The probability of selecting Brands B and C is 0.3. #c. At least one of the two brands B and C#
07

Calculate complementary probability

To calculate the probability of selecting at least one of the two brands B and C, we can use the complementary probability. So, we can determine the probability of not selecting either B or C and subtract this probability from 1. We have three brands (A, D, E) left to choose from if we do not include B and C. We need to choose three out of these three: \[_3C_3 = \frac{3!}{3! 0!} = 1\] So, there is only 1 combination without Brands B and C.
08

Calculate the probability

Now, let's calculate the probability of selecting at least one of the two brands B and C: \[P(\textrm{at least one of B and C}) = 1 - \frac{\textrm{Number of combinations without Brands B and C}}{\textrm{Total combinations}}\] \[P(\textrm{at least one of B and C}) = 1 - \frac{1}{10} = \frac{9}{10} = 0.9\] The probability of selecting at least one of the two brands B and C is 0.9.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinatorics
Combinatorics is a branch of mathematics that deals with counting and arrangements of distinct items. It's the science behind organizing different objects into sets following specific rules.

When we talk about combinatorics, we refer to two main types of techniques: permutations and combinations. Permutations deal with the arrangement of objects where order matters, whereas combinations focus on groups where order doesn't matter. Think of permutations as ways to arrange books on a shelf and combinations as selecting books to take on a trip.

In the context of our druggist problem, we are interested in combinations since the order of selecting aspirin brands doesn't matter—only which brands are selected.
Combination formula
The combination formula is a mathematical way to find the number of ways to select objects from a larger set. It is given by:

\[ _nC_r = \frac{n!}{r!(n-r)!} \]

Here, \(n\) represents the total number of available items, and \(r\) is the number of items to choose. The "!" symbol denotes factorial, which means multiplying the series of descending natural numbers.

For example, \(5! = 5 \times 4 \times 3 \times 2 \times 1 = 120\).

In our exercise, we are using the combination formula to choose 3 brands from 5. This helps us systematically determine all possible ways to make this selection. It's a handy tool in probability to simplify determining possible outcomes.
Teaching probability concepts
Teaching probability involves breaking down the likelihood of events occurring in a clear, understandable manner. Probability gives us a way to quantify uncertainty, helping us to make informed decisions.

Let's explore the key ideas through our problem:
  • Probability is calculated as the ratio of the number of favorable outcomes to the total number of possible outcomes.
  • The probability of a certain event "A" is represented by \(P(A)\).
  • For example, selecting Brand B involves finding combinations that specifically include B, then comparing it against all possible selections.
This methodical reasoning forces us to think clearly about the variables involved, fostering solid problem-solving skills.
Mathematics problem solving
Mathematics problem solving is an art of deciphering what is unknown using mathematical concepts and techniques. It requires clarity and a step-by-step approach.

Solving the probability problem in our exercise, we take the following steps:
  • Define the problem clearly: understand what is being asked.
  • Use relevant formulas: apply the combination formula to find possible selections.
  • Break down the problem: tackle parts one by one, like solving for Brand B first, then both Brand B and C, and finally considering at least one of them.
By consistently applying these steps, we can solve complex problems easily. It encourages logical reasoning, critical thinking, and a curious mindset.

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