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Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false. If \(A\) and \(B\) are events of an experiment, then $$ P(A \cap B)=P(A \mid B) \cdot P(B)=P(B \mid A) \cdot P(A) $$

Short Answer

Expert verified
The statement is true. The probability of the intersection of events \(A\) and \(B\) can be expressed in both ways, as the product of the conditional probability and the probability of the conditioned event: $$ P(A \cap B)=P(A \mid B) \cdot P(B)=P(B \mid A) \cdot P(A) $$ This is derived from the definitions of conditional probability and rearranging the formulas accordingly.

Step by step solution

01

Understand Probability Concepts

Before we dive into the main problem, let's understand some key probability concepts that will be helpful. 1. The probability of an event \(A\), denoted \(P(A)\), is a number between 0 and 1 that represents the likelihood of event \(A\) occurring. 2. The intersection of events, denoted \(A \cap B\), represents the set of outcomes where both events \(A\) and \(B\) occur. 3. The conditional probability of an event \(A\), given that event \(B\) happens, is denoted: \(P(A \mid B)\). Now let's analyze the given statement: \(P(A \cap B)=P(A \mid B) \cdot P(B)=P(B \mid A) \cdot P(A)\).
02

Break Down the Statement

We can break the given statement into two parts: 1. \(P(A \cap B)=P(A \mid B) \cdot P(B)\) 2. \(P(A \cap B)=P(B \mid A) \cdot P(A)\) Let's try to prove each of these two statements separately.
03

Prove \(P(A \cap B) = P(A \mid B) \cdot P(B)\)

The conditional probability of an event \(A\), given that event \(B\) happens, is defined as: $$ P(A \mid B) = \frac{P(A \cap B)}{P(B)} $$ To prove the statement, we can rearrange the formula for conditional probability: $$ P(A \cap B) = P(A \mid B) \cdot P(B) \, (*) $$ This part of the statement is true because we have derived formula (*) from the definition of conditional probability.
04

Prove \(P(A \cap B) = P(B \mid A) \cdot P(A)\)

Similarly, the conditional probability of an event \(B\), given that event \(A\) happens, is defined as: $$ P(B \mid A) = \frac{P(A \cap B)}{P(A)} $$ To prove this statement, we can rearrange the formula for conditional probability: $$ P(A \cap B) = P(B \mid A) \cdot P(A) \, (**) $$ This part of the statement is also true because we have derived formula (**) from the definition of conditional probability.
05

Confirm the Given Statement

At this point, we have proved both parts of the statement: 1. \(P(A \cap B)=P(A \mid B) \cdot P(B)\), by formula (*) 2. \(P(A \cap B)=P(B \mid A) \cdot P(A)\), by formula (**) Therefore, the given statement is true. The probability of the intersection of events \(A\) and \(B\) can be expressed in both ways, as the product of the conditional probability and the probability of the conditioned event. To summarize: $$ P(A \cap B)=P(A \mid B) \cdot P(B)=P(B \mid A) \cdot P(A) $$ The statement is true, and we have explained the reasoning above.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability of Intersection
Understanding the probability of intersection can feel like fitting together pieces of a puzzle—each piece represents an event, and the intersection is where these events coincide. When we speak about the probability of the intersection of two events, typically denoted as \(P(A \cap B)\), we are essentially looking for the likelihood of both events \(A\) and \(B\) happening simultaneously.

Picture a classic deck of cards—finding the probability of drawing a red card that is also a king involves looking for where these two qualities, 'being red' and 'being a king,' overlap. There are two such cards in a deck of 52, so \(P(A \cap B)\) in this case would be \(\frac{2}{52}\) or \(\frac{1}{26}\). The intersection encompasses scenarios that satisfy both event conditions at once, which is a core concept in probability theory.
Definition of Conditional Probability
The definition of conditional probability is like having a flashlight that shines a light on just one part of the probability universe. It answers the question: 'Given that one event has occurred, how does that impact the likelihood of another event occurring?' In formal terms, the probability that event \(A\) occurs given that \(B\) has already occurred, denoted \(P(A \mid B)\), is expressed mathematically as \(\frac{P(A \cap B)}{P(B)}\), assuming \(P(B)\) is not zero.

To illustrate, if event \(B\) envelopes event \(A\) in our universe of events, the occurrence of \(B\) sets the stage, limiting our scope to just that. This, in turn, directly affects the probability of \(A\) happening. If you know it's raining (event \(B\)), what's the probability that people will carry umbrellas (event \(A\))? The rain doesn’t change the number of people with umbrellas—it changes the probability we assign to encountering them. Conditional probability is vital for understanding and calculating complex probabilistic relationships.
Probability Concepts
Diving into the realm of probability concepts, we immerse ourselves in a world governed by chance and likelihood. The fundamental concept is the probability of an event \(A\), written as \(P(A)\), which measures how likely it is for that event to occur on a scale from 0 (impossible event) to 1 (certain event).

Other key concepts include the aforementioned conditional probability and the intersection of events. Together, they form the building blocks for more advanced topics such as independent events, where the probability of one event does not affect the other, and mutually exclusive events, which cannot occur simultaneously. Understanding these principles is essential for anyone venturing into the world of statistics, as they apply not only in textbooks but in real-life scenarios ranging from predicting weather to calculating risks in finance.

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