/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 51 Let \(E\) and \(F\) be events su... [FREE SOLUTION] | 91Ó°ÊÓ

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Let \(E\) and \(F\) be events such that \(F \subset E\). Find \(P(E \mid F)\) and interpret your result.

Short Answer

Expert verified
The conditional probability \(P(E \mid F)\) is 1. This means if event F occurs, then event E is certain to occur, since F is a subset of E and all outcomes in F are included in E.

Step by step solution

01

Identify the intersection of events E and F

Since F is a subset of E, it means that all outcomes in event F are also included in event E. Therefore, the intersection of E and F, denoted by E ∩ F, is simply F itself: \[E \cap F = F\]
02

Calculate the probabilities P(E ∩ F) and P(F)

Given that \(E \cap F = F\), for the numerator, the probability of the intersection is the same as the probability of F: \[P(E \cap F) = P(F)\] As for the denominator, we don't have any information about P(F) from the given exercise. So, we'll leave it as is, denoting it as P(F).
03

Apply the formula for conditional probability

Now that we have the probabilities for \(P(E \cap F)\) and \(P(F)\), we can apply the formula for conditional probability: \[P(E \mid F) = \frac{P(E \cap F)}{P(F)}\] By substituting \(P(E \cap F) = P(F)\): \[P(E \mid F) = \frac{P(F)}{P(F)}\] Since P(F) > 0, we can simplify this expression: \[P(E \mid F) = 1\]
04

Interpret the result

The result P(E | F) = 1 indicates that if event F occurs, then event E is certain to occur as well. This is consistent with the given condition that F is a subset of E, meaning once we know F has occurred, E must also have occurred since all outcomes in F are included in E.

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