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A halogen desk lamp produced by Luminar was found to be defective. The company has three factories where the lamps are manufactured. The percentage of the total number of halogen desk lamps produced by each factory and the probability that a lamp manufactured by that factory is defective are shown in the accompanying table. What is the probability that the defective lamp was manufactured in factory III? $$ \begin{array}{ccc} \hline & & \text { Probability of } \\ \text { Factory } & \text { Percent of } & \text { Defective } \\ \text { Total Production } & \text { Component } \\ \hline \text { I } & 35 & .015 \\ \hline \text { II } & 35 & .01 \\ \hline \text { III } & 30 & .02 \\ \hline \end{array} $$

Short Answer

Expert verified
The probability that a defective lamp was manufactured in factory III is \(\frac{6}{43}\).

Step by step solution

01

Convert percentages to probabilities

To work with the Bayesian theorem, we need to convert the percentages of the total number of halogen desk lamps produced by each factory to probabilities. Divide the percentages by 100 to get the probabilities. Probability that a lamp is produced by factory I: \(P(\text{Factory I}) = \frac{35}{100}\) Probability that a lamp is produced by factory II: \(P(\text{Factory II}) = \frac{35}{100}\) Probability that a lamp is produced by factory III: \(P(\text{Factory III}) = \frac{30}{100}\)
02

Apply Bayesian theorem

To find the probability that the defective lamp was manufactured in factory III, we will apply the Bayesian theorem which is: \(P(A|B) = \frac{P(B|A) * P(A)}{P(B)}\) Here, we want to find \(P(\text{Factory III | Defective})\) We know: - \(P(\text{Defective | Factory III}) = 0.02\) - \(P(\text{Factory III}) = \frac{30}{100}\) We need to find the marginal probability \(P(\text{Defective})\). We can find it using the law of total probability: \(P(\text{Defective}) = P(\text{Defective | Factory I}) * P(\text{Factory I}) + P(\text{Defective | Factory II}) * P(\text{Factory II}) + P(\text{Defective | Factory III}) * P(\text{Factory III}) \)
03

Calculate the marginal probability

Let's calculate the marginal probability of a lamp being defective: \(P(\text{Defective}) = 0.015 * \frac{35}{100} + 0.01 * \frac{35}{100} + 0.02 * \frac{30}{100} \) After calculating the above expression, we get: \(P(\text{Defective}) = \frac{43}{2000}\)
04

Calculate the conditional probability

Now, let's use the Bayesian theorem to find the probability that the defective lamp was manufactured in factory III: \(P(\text{Factory III | Defective}) = \frac{P(\text{Defective | Factory III}) * P(\text{Factory III})}{P(\text{Defective})}\) Plugging the values into the equation: \(P(\text{Factory III | Defective}) = \frac{0.02 * \frac{30}{100}}{\frac{43}{2000}}\) After solving, we get: \(P(\text{Factory III | Defective}) = \frac{6}{43}\) The probability that a defective lamp was manufactured in factory III is \(\frac{6}{43}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bayesian Theorem
The Bayesian theorem, also known as Bayes' rule, is a powerful tool in probability theory for updating the likelihood of a hypothesis as more evidence becomes available. It connects conditional probabilities, marginal probabilities, and the joint probability of two events.

In the given exercise, we use the Bayesian theorem to determine the likelihood that a defective lamp came from a specific factory (Factory III) given that the lamp is known to be defective. The theorem's formula can be given by:
\[ P(A|B) = \frac{P(B|A) \times P(A)}{P(B)} \]
where:
  • \( P(A|B) \) is the probability of event A given that B has occurred,
  • \( P(B|A) \) is the probability of event B given that A has occurred,
  • \( P(A) \) is the probability of event A, and
  • \( P(B) \) is the probability of event B (the marginal probability).
In our context, A is the event of a lamp being manufactured in Factory III, and B is the event of a lamp being defective. By obtaining the probability of a lamp being defective from each factory and the overall probability of a lamp being defective, we can use Bayes' theorem to invert the conditionality and estimate the sought probability.

The theorem wonderfully illustrates how we can deduce new information by combining prior knowledge with new evidence, a process known as Bayesian inference.
Conditional Probability
Conditional probability is a measure of the probability of an event given that another event has occurred. If the event of interest is A and the event it is conditioned on is B, the conditional probability of A given B is written as \( P(A|B) \).

In real-world applications, such as the exercise we're discussing, conditional probability allows us to answer questions about the likelihood of an event happening under certain conditions or constraints. For the defective lamp scenario, we wanted to calculate the conditional probability that a lamp was produced by Factory III given that the lamp is known to be defective. This was represented as \( P(\text{Factory III | Defective}) \).

Key to Understanding

It's crucial to understand that conditional probability is not the same as the probability of both events happening together; rather, it's the probability of one event under the specific condition that we know the other event has already occurred. For students, grasping this difference is essential to apply conditional probability correctly in various situations.
Marginal Probability
Marginal probability, also often referred to as the unconditional probability, is the probability of an event occurring regardless of the outcome of other events. It is called 'marginal' because in the context of probability tables or spreadsheets, it is typically found in the right-most column or the bottom row – literally in the margins.

In the exercise, we calculated the marginal probability of a lamp being defective, not specific to any factory. This overall probability of defectiveness, \( P(\text{Defective}) \), takes into account all the ways a lamp could be defective across the different factories.

How to Calculate It

We used the law of total probability to calculate the marginal probability, which involved summing up the individual probabilities of a lamp being defective from all factories weighted by the probability of a lamp coming from each respective factory. This formula for the law of total probability is particularly useful:
\[ P(B) = \sum\limits_{i}(P(B|A_i) \times P(A_i)) \]
where \( A_i \) are the different sources or conditions through which event B (a lamp being defective) can occur. Students should recognize marginal probability as a fundamental concept that often serves as the foundation for more complex probability calculations, like those involving conditional probabilities and Bayes' theorem.

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Most popular questions from this chapter

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