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Let \(S=\left\\{s_{1}, s_{2}, s_{3}, s_{4}\right\\}\) be the sample space associated with an experiment having the probability distribution shown in the accompanying table. If \(A=\left\\{s_{1}, s_{2}\right\\}\) and \(B=\left\\{s_{1}, s_{3}\right\\}\), find a. \(P(A), P(B)\) b. \(P\left(A^{c}\right), P\left(B^{c}\right)\) c. \(P(A \cap B)\) d. \(P(A \cup B)\)

Short Answer

Expert verified
The short answer version of the given problem is: a. \(P(A) = p_1 + p_2, P(B) = p_1 + p_3\) b. \(P(A^c) = 1 - (p_1 + p_2), P(B^c) = 1 - (p_1 + p_3)\) c. \(P(A \cap B) = p_1\) d. \(P(A \cup B) = p_1 + p_2 + p_3\)

Step by step solution

01

Probabilities of Events A and B

We have, \(A=\{s_1, s_2\}\) and \(B=\{s_1, s_3\}\). To find the probability of events A and B, we sum the probabilities of the individual outcomes in each event: \[ P(A) = P(s_1) + P(s_2) = p_1 + p_2 \] \[ P(B) = P(s_1) + P(s_3) = p_1 + p_3 \] Step 2: Calculate \(P\left(A^{c}\right), P\left(B^{c}\right)\)
02

Probabilities of the Complements of Events A and B

To find the probability of the complement of events A and B, we use the formula: \[P(A^c) = 1 - P(A)\] \[P(B^c) = 1 - P(B)\] By substituting the values we calculated in Step 1, we get: \[ P(A^c) = 1 - (p_1 + p_2) \] \[ P(B^c) = 1 - (p_1 + p_3) \] Step 3: Calculate \(P(A \cap B)\)
03

Probability of Intersection between Events A and B

To find the probability of the intersection between events A and B, we determine the common elements in both sets and calculate the probability of the outcomes. \[ A \cap B = \{s_1\} \] \[ P(A \cap B) = P(s_1) = p_1 \] Step 4: Calculate \(P(A \cup B)\)
04

Probability of Union of Events A and B

To find the probability of the union of events A and B, we use the formula: \[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \] By substituting the values we calculated in Steps 1 and 3, we get: \[ P(A \cup B) = (p_1 + p_2) + (p_1 + p_3) - p_1 = p_1 + p_2 + p_3 \] Now we have the probability of the events A and B, the probability of their complements, the probability of their intersection, and the probability of their union.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Space
The concept of a sample space is foundational in the study of probability and serves as the starting point for many probability problems. The sample space of an experiment is the set of all possible outcomes of that experiment. In mathematical terms, if an experiment can result in any outcome within the set \(S\), then \(S\) is our sample space. It's important for students to understand that the sample space should include every conceivable outcome to ensure that the probabilities of all events total to one.
For instance, if you're rolling a six-sided die, the sample space is \(S = \{1, 2, 3, 4, 5, 6\}\), representing each possible outcome when the die is rolled. However, it's crucial that students remember that the nature of the sample space can change drastically depending on the experiment. For example, if you are drawing a card from a standard deck of 52 cards, the sample space will consist of all 52 cards. A well-defined sample space sets the stage for finding probabilities accurately.
Probability of Events
When we refer to the probability of events, we’re discussing the likelihood that a particular event will occur. An event is a specific outcome or a combination of outcomes from the sample space. The probability of any event \(A\) can be found by summing the probabilities of the individual outcomes that make up \(A\).
To visualize this better, consider the previous example of rolling a die. If event \(A\) is defined as rolling an even number, then the event \(A\) includes the outcomes 2, 4, and 6. The probability of event \(A\) happening is calculated by adding the probabilities of rolling a 2, 4, or 6. Assuming a fair die, the probability of each outcome is \(1/6\), so the probability of event \(A\) would be \(1/6 + 1/6 + 1/6 = 1/2\).

Interpreting Probabilities

Probabilities range from 0 to 1, where 0 indicates impossibility and 1 indicates certainty. For practical reasons, it can also be expressed as percentages. A probability of \(0.5\) or \(50%\) like in the die example suggests that the event is as likely to occur as not.
Complements of Events
The concept of the complement of an event is quite like looking at the flip side of a coin. If you have an event \(A\), its complement, denoted by \(A^c\), includes all outcomes in the sample space that are not in \(A\). In other words, the complement of an event is what happens when the event does not occur.
For a simple relation: \[ P(A^c) = 1 - P(A) \] This formula is derived from the fact that the sum of the probabilities of all outcomes (events plus their complements) in a sample space is equal to 1.

Using Complements

Sometimes it is easier to calculate the probability of the complement and then use it to find the probability of the event itself. For example, if it’s hard to calculate the probability of winning a game, it might be easier to calculate the probability of losing and then subtracting from 1 to find the probability of winning. Understanding complements is particularly useful for avoiding extensive calculations and can be a time-saver in many scenarios.
Probability of Intersection
The probability of intersection refers to the likelihood that two events, say \(A\) and \(B\), will occur simultaneously. Using set language, this is often represented as \(A \cap B\) and is only concerned with the outcomes common to both events.
To calculate \(P(A \cap B)\), you identify the shared outcomes of events \(A\) and \(B\) and sum their probabilities. For events that cannot happen at the same time (mutually exclusive), the probability of their intersection is zero because they have no common outcomes.

Importance of Independent and Dependent Events

When dealing with two independent events, the probability of their intersection is the product of their individual probabilities. This changes for dependent events, where the occurrence of one influences the probability of the other. In such cases, additional rules and formulas are applied.
Probability of Union
In contrast to intersection, the probability of union of two events \(A\) and \(B\), denoted \(A \cup B\), covers any outcome that is in either event or in both. It represents the probability that either event \(A\), event \(B\), or both will occur.
To calculate this probability, the general formula is:\[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \] This is because when we add \(P(A)\) and \(P(B)\), we count the probability of \(A \cap B\) twice, so we need to subtract it once to get the true probability of the union.

Additivity of Probabilities

This calculation method is based on an important principle called the additivity of probabilities, which states that the probability of the occurrence of at least one of several events is the sum of their individual probabilities, less the sum of the probabilities of their intersections. Understanding this principle is crucial when events are not mutually exclusive and can share outcomes.

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Most popular questions from this chapter

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