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Chapter 21: Q21-23P (page 718)

Draw structures of the step-growth polymers you would expect to obtain from the following reactions:

Short Answer

Expert verified

a.

b.

c.

Step by step solution

01

Polymer formed in (a)

Formation of Polyether takes place by the removal of halogen from one reactant and halogen from another reactant.

Formation of polyether

02

Polyester is formed in (b)

By the addition of acid removal of water takes place, by removal of 鈥揙H from alcohol and hydrogen from carboxylic acid and then polymerisation takes place. Then it leads to the formation of polyester.

Formation of polyester

03

 Step 3: Polyamide is formed in (c)

In the formation of amide takes place by the removal of hydrogen from amine and removal of chlorine from another reactant. After this polymerisation takes place.

Formation of polyamide

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Most popular questions from this chapter

Question: 21-63 Polyimides with the structure shown are used as coatings on glass and plastics to improve scratch resistance. How would you synthesize a polyimide? (See Problem 21-39.)

The hydrolysis of a biological thioester to the corresponding carboxylate is often more complex than the overall result might suggest. The conversion of succinyl CoA to succinate in the citric acid cycle, for instance, occurs by initial formation of an acyl phosphate, followed by reaction with guanosine diphosphate (GDP, a relative of adenosine diphosphate [ADP]) to give succinate and guanosine triphosphate (GTP, a relative of ATP). Suggest mechanisms for both steps.

21-43 The following reaction, called the benzilic acid rearrangement, takes place by typical carbonyl group reactions. Propose a mechanism (Ph=phenyl).

Propose structures for compounds that have the following formulas and IR absorptions:

(a) C6H12O2, 1735 cm-1

(b) C4H9NO, 1650 cm-1

(c) C4H5ClO, 1780 cm-1

How would you convert N-ethylbenzamide to each of the following products?

(a) Benzoic acid (b) Benzyl alcohol (c)C6H5CH2NHCH2CH3

See all solutions

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