/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q24P How could you prepare the follow... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 17: Q24P (page 820)

How could you prepare the following compound using a starting material that contains no more than three carbons?

Short Answer

Expert verified

A reaction followed as:

Step by step solution

01

LDA reagent

Lithium di-isopropyl amide is the most basic reagent is used to abstract the proton from the molecule. It is used in the aldol condensation to form the enolate ion from the enol or ketone by abstracting the proton for further reaction.

02

Formation of the compound

The given compound is formed by the acetone followed by the formation of the enolate ion than in reaction with the alkyl halide the alkyl group attaches to the enolate oxygen and the removal of the halide ion occurs and forms the desired product.

03

Mechanism

Mechanism followed as:

  1. Acetone reacts with LDA

  2. Enolate ion formed

  3. Enolate reacts with ethyl bromide

  4. Ethyl attack on enolate oxygen

  5. Removal of bromide on desired product formed

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Explain why a racemic mixture is formed when (R)-2-methylpentanal is dissolved in an acidic or basic solution.

Explain why the following bromoketone forms different bicyclic compounds under different reaction conditions:

Problem: starting with bromocyclohexane, how can each of the following compounds be prepared?

Question: Explain why the 伪-hydrogen of an N,N-disubstituted amide is less acidic (pKa= 30) than the 伪-hydrogen of an ester (pKa= 25).

Explain why the following carboxylic acids cannot be prepared by a malonic ester synthesis:
See all solutions

Recommended explanations on Chemistry Textbooks

Chemical Analysis

Read Explanation

Physical Chemistry

Read Explanation

Kinetics

Read Explanation

Chemical Reactions

Read Explanation

The Earths Atmosphere

Read Explanation

Chemistry Branches

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.