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Chapter 5: Q 10TP (page 190)

Use what the curved arrows tell you about electron movement to determine the product(s) of each reaction step.

Short Answer

Expert verified

The first step is to use a curved arrow.

鈥� As new covalent bonds are formed and existing covalent bonds are destroyed, electrons move in curved arrows.

鈥� Each arrow represents the movement of two electrons (an electron pair) from a single atom to an electrophile (nucleophile) at the end of the arrow (at the point of the arrow).

鈥� The arrow's tail denotes the location of the reactant's electrons; the tail always starts at a lone pair or a bond.

鈥� The arrow's head always points to an atom or a bond, indicating where these same electrons end up in the result.

Step by step solution

01

Step-by-Step Solution

The first step is to use a curved arrow.

鈥� As new covalent bonds are formed and existing covalent bonds are destroyed, electrons move in curved arrows.

鈥� Each arrow represents the movement of two electrons (an electron pair) from a single atom to an electrophile (nucleophile) at the end of the arrow (at the point of the arrow).

鈥� The arrow's tail denotes the location of the reactant's electrons; the tail always starts at a lone pair or a bond.

鈥� The arrow's head always points to an atom or a bond, indicating where these same electrons end up in the result.

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Most popular questions from this chapter

Given the reaction coordinate diagram for the reaction of A to form G, answer the following questions:

a. How many intermediates are formed in the reaction?

b. Which letters represent transition states?

c. What is the fastest step in the reaction?

d. Which is more stable,AorG?

e. DoesAorEform faster fromC?

f. What is the reactant of the rate-determining step?

g. Is the first step of the reaction exergonic or endergonic?

h. Is the overall reaction exergonic or endergonic?

i. Which is the more stable intermediate?

j. Which step in the forward direction has the largest rate constant?

k. Which step in the reverse direction has the smallest rate constant?

Question: Determine the degree of unsaturation for hydrocarbons with the following molecular formulas:

a. C20H34 b. C8H16 c. C12H20 d. C40H56

Draw curved arrows to show the movement of the electrons in each step of the following reaction sequences. (Hint: You can tell how to draw the arrows for each step by looking at the products that are formed in that step as a result of the movement of electrons.)

Draw structures for the following:

a. (2E,4E)-1-chloro-3-methyl-2,4-hexadiene

b. (3Z,5E)-4-methyl-3,5-nonadiene

c. (3Z,5Z)-4,5-dimethyl-3,5-nonadiene

d. (3E,5E)-2,5-dibromo-3,5-octadiene

What is the molecular formula for each of the following?

  1. a 4-carbon hydrocarbon with two p bonds and no rings
  2. a 10-carbon hydrocarbon with one p bond and 2 rings
See all solutions

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