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Chapter 22: Q27. (page 903)

Question: What two monomers are needed to prepare nylon 6,10?

Short Answer

Expert verified

Answer

Monomers of nylon-6,10- sebacoyl chloride and hexamethylene diamine

Step by step solution

01

Step-by-Step Solution Step 1: Condensation polymerization

Polymerization reactions that involve the removal of small molecules like water, or methanol are called condensation polymerization reactions.

The condensation reaction occurs between a nucleophilic center and an electrophilic center.

Polyesters, polyamides are examples of polymers formed by condensation polymerization.

02

Polyamides

Polyamides are synthetic polymers formed by the condensation polymerization between acid chlorides and amines.

Hydrochloric acid molecules are removed as a byproduct during the polymerization reaction.

An example of polyamide is nylon, a strong and durable polymer that resembles silk.

03

Synthesis of nylon-6,10

Nylons are named based on the number of carbon atoms in the acid chloride and amine that condenses to form the polymer.

The first number represents the amine and the second number represents the acid chloride.

Therefore, the monomers of nylon-6,10 are amines with 6 carbon atoms and an acid chloride with 10 carbon atoms

That is, nylon-6,10 is a polymer of sebacoyl chloride and hexamethylene diamine.

Retro analysis of nylon-6,10

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Most popular questions from this chapter

Question: Rank the compounds in each group in order of increasing reactivity in nucleophilic acyl substitution.

a.C6H5CO2CH3,C6H5COCl,C6H5CONH2b.CH3CH2CO2H,(CH3CH2CO)2O,CH3CH2CONHCH3
  1. What orbitals are used to form the indicated bonds in 伪-sinensal?
  2. In what type of orbitals do the lone pairs on Oreside?

Draw the products formed (including stereoisomers) when each compound is reduced with NaBH4in CH3OH.

Draw the products (including stereochemistry) of the following reactions.

Draw the products formed when CH3COCH2CH2CH=CH2is treated with each reagent: (a)LiAlH4, then H2O ; (b) NaBH4in CH3OH ; (c) H2(1 equiv), Pd-C; (d)H2(excess), Pd-C; (e)NaBH4 (excess) inCH3OH ; (f) NaBD4in CH3OH
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