/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q.62 Explain why the reaction of 2-br... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Explain why the reaction of 2-bromopropane withNaOCOCH3 gives(CH3)2CHOCOCH3 exclusively as product, but the reaction of 2-bromopropane with NaOCH2CH3gives a mixture of (CH3)2CHOCH2CH3(20%) and CH3CH=CH2(80%).

Short Answer

Expert verified

The reason is acetate ion is a powerful nucleophile than a base and only promotes substitution product. But ethoxides act both as a strong base and a strong nucleophile.

Step by step solution

01

Function of ethoxide

Ethoxide is a strong base as well as a strong nucleophile. Hence they give both an elimination and a substitution product.

02

Function of acetate anion

Acetate anion acts only as a good nucleophile. Hence, they exclusively give a substitution product.

Keeping into account all the key points, the products with their mode of reaction are shown below:-

Representation of the substituted and eliminated products

The difference in the concentration is observed here because acetate ion is a powerful nucleophile than a base and only promotes substitution product. In contrast, ethoxides act both as a strong base and a strong nucleophile. Hence, they promote both substitution and elimination products.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.