/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q57. Question: Draw a stepwise, detai... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 9: Q57. (page 378)

Question: Draw a stepwise, detailed mechanism for the following reaction.

Short Answer

Expert verified

Answer

The mechanism of the reaction is as shown below.

Step by step solution

01

Step-by-Step SolutionStep 1: Stability of carbocation

During the (unimolecular) reaction, the most stable carbocation intermediate will be formed if the rearrangement of alkyl shift or hydride shift does not lead to the formation of the most stable carbocation

02

The mechanism of the given reaction

This reaction takes place in the presence of a sulfuric acid catalyst.

The secondary carbocation becomes the most stable 3掳carbocationdue to the alkyl shift. Then, will be eliminated, and it leads to the formation of the respective alkene

Mechanism of the reaction

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Question: Explain why two substitution products are formed in the following reaction.

Question: Draw the substitution product formed (including stereochemistry) when (R)-hexan-2-ol is treated with each series of reagents: (a) NaH, followed by CH3I ; (b) TsCl and pyridine, followed by NaOCH3 ; (c) PBr3, followed by NaOCH3. Which two routes produce identical products?

Question: Sometimes carbocation rearrangements can change the size of a ring. Draw a stepwise, detailed mechanism for the following reaction.

Question:Propranolol, an antihypertensive agent used in the treatment of high blood pressure, canbe prepared from 1-naphthol, epichlorohydrin, and isopropyl amine using two successivenucleophilic substitution reactions. Devise a stepwise synthesis of propranolol from thesestarting materials.

Question: a) What is the major alkene formed when A is dehydrated with H2SO4 ? (b) What is the major alkene formed when A is treated with POCl3and pyridine? Explain why the major product is different in these reactions.
See all solutions

Recommended explanations on Chemistry Textbooks

Organic Chemistry

Read Explanation

Chemistry Branches

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Inorganic Chemistry

Read Explanation

The Earths Atmosphere

Read Explanation

Making Measurements

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.