/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q22E It is proposed to store聽1kW.h=3... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 4: Q22E (page 1014)

It is proposed to store1kW.h=3.6脳106Jof electrical energy in a uniform magnetic field with magnitude0.6T. (a) What volume (in vacuum) must the magnetic field occupy to store this amount of energy? (b) If instead this amount of energy is to be stored in a volume (in vacuum) equivalent to a cube40cmon a side, what magnetic field is required?

Short Answer

Expert verified

a) V=25.1m3

b)B=11.9T

Step by step solution

01

The formulas involved in the given problem

The energy density can be calculated by u=UVor u=B22渭0.

Equate both the equations and find the volume.

02

Calculate the volume

Given thatU=3.6脳106J,l=40cmandB=0.6T. Using both the energy density equations

UV=B22渭0V=2渭0UB2V=2脳4蟺脳10-7脳3.6脳1060.62V=25.1m3

The side of the cube isl=40cm. The volume will be 0.064m3.

B=2渭0UVB=2脳4蟺脳10-7脳3.6脳1060.064B=11.9T

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The potential difference across the terminals of a battery is 8.40 V when there is a current of 1.50 A in the battery from the negative to the positive terminal. When the current is 3.50 A in the reverse direction, the potential difference becomes10.20 V . (a) What is the internal resistance of the battery? (b) What is the emf of the battery?

Questions: When a thunderstorm is approaching, sailors at sea sometimes observe a phenomenon called 鈥淪t. Elmo鈥檚 fire,鈥� a bluish flickering light at the tips of masts. What causes this? Why does it occur at the tips of masts? Why is the effect most pronounced when the masts are wet? (Hint: Seawater is a good conductor of electricity.)


An electron at pointAinFig. E27.15has a speedv0of1.41脳106m/sFind (a) the magnitude and direction of the magnetic field that will cause the electron to follow the semicircular path fromAtoB, and (b) the time required for the electron to move fromAtoB.

In Europe the standard voltage in homes is 220 V instead of the 120 used in the United States. Therefore a 鈥�100-W鈥� European bulb would be intended for use with a 220-V potential difference (see Problem 25.36). (a) If you bring a 鈥�100-W鈥� European bulb home to the United States, what should be its U.S. power rating? (b) How much current will the 100-W European bulb draw in normal use in the United States?

When a resistor with resistance Ris connected to a 1.50-V flashlight battery, the resistor consumes 0.0625 W of electrical power. (Throughout, assume that each battery has negligible internal resistance.) (a) What power does the resistor consume if it is connected to a 12.6-V car battery? Assume that Rremains constant when the power consumption changes. (b) The resistor is connected to a battery and consumes 5.00 W. What is the voltage of this battery?

See all solutions

Recommended explanations on Physics Textbooks

Electrostatics

Read Explanation

Electromagnetism

Read Explanation

Geometrical and Physical Optics

Read Explanation

Space Physics

Read Explanation

Mechanics and Materials

Read Explanation

Solid State Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.