/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q22E Question: A hollow aluminum cyli... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Question: A hollow aluminum cylinder is 2.50 mlong and has an inner radius of 2.75 cmand an outer radius of 4.60 cm. Treat each surface (inner, outer, and the two end faces) as an equipotential surface. At room temperature, what will an ohmmeter read if it is connected between (a) the opposite faces and (b) the inner and outer surfaces?

Short Answer

Expert verified
  1. The ohmmeter read if it is connected between the opposite faces isR=1.61x10-5Ω
  2. The ohmmeter read if it is connected between the inner and outer surfaces isR=9.01x10-10Ω

Step by step solution

01

Determine the ohmmeter read if it is connected between the opposite faces

a. The cross-sectional area of the cylinder is

Now, we know the formula

R=ÒÏLA

Substitute the given values

Therefore, the ohmmeter reading if the ohmmeter is connected between the opposite faces is

02

Determine the formula to find the ohmmeter reading if it is connected between the inner and outer surfaces

b. The current flows radially inward or outward (which depends on the direction of the current) when the ohmmeter is connected between the inner and outer surfaces.

Let us assume a thin cylindrical shell of length L, radius r, and thickness dr(the outer radius is approximately equal to inner radius)

We know, the current moves radially, so, the current moves along a distance L = dr and through a cross-sectional area .

Now, the resistance of this conductor is

The current that flows radially from , the resistance is

03

Determine the ohmmeter reading when it is placed between the inner and outer surfaces

Use the formula found above,

R=ÒÏ2Ï€³¢lnroutrin

Substitute the given values

Therefore, when the ohmmeter is placed between the inner and outer surfaces, the ohmmeter reading is found to be

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A particle of mass 0.195 g carries a charge of-2.50×10-8C. The particle is given an initial horizontal velocity that is due north and has magnitude4.00×104m/s. What are the magnitude and direction of the minimum magnetic field that will keepthe particle moving in the earth’s gravitational field in the samehorizontal, northward direction?

BIO Transmission of Nerve Impulses. Nerve cells transmit electric

signals through their long tubular axons. These signals propagate due to a

sudden rush of Na+ions, each with charge +e, into the axon. Measurements

have revealed that typically about 5.6×1011Na+ions enter each meter of the

axon during a time of . What is the current during this inflow of charge

in a meter of axon?

A resistor with resistance Ris connected to a battery that has emf 12.0 V and internal resistance r=0.40Ω. For what two values of R will the power dissipated in the resistor be 80.0 W ?

(a) What is the potential difference Vadin the circuit of Fig. P25.62? (b) What is the terminal voltage of the 4.00-Vbattery? (c) A battery with emf and internal resistance 0.50Ωis inserted in the circuit at d, with its negative terminal connected to the negative terminal of the 8.00-Vbattery. What is the difference of potential Vbcbetween the terminals of the 4.00-Vbattery now?

An 18-gauge copper wire (diameter 1.02 mm) carries a current

with a current density of 3.2×106Am2. The density of free electrons for

copper is8.5×1028electrons per cubic meter. Calculate (a) the current in

the wire and (b) the drift velocity of electrons in the wire.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.