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Chapter 19: Q. 4 (page 543)

A 2000 cm3 container holds 0.10 mol of helium gas at 300掳C. How much work must be done to compress the gas to 1000 cm3 at (a) constant pressure and (b) constant temperature?

Short Answer

Expert verified

a. The value of work done at constant pressure is 240J

b. The value of work done at constant volume is 330J

Step by step solution

01

Definition of work done

The work done has represented as energy that is transferred between system and environment.

02

Step  2: Finding the work done energy. 

The value of the changeable volume is

V2-V1=1000-2000脳cm3=-1000脳cm3

the equation of real gas is localid="1649077116383" p=nRTV1

So the work done is

W=-nRTV1鈭�V

Now the temperature in Kelvin is ((300+273)= 573K

a. The value of work done at constant pressure

W=-(0.10)(8.314J/mol.K脳500K200脳10-6m3(-1000脳10-6m3)=240J

b. The value of work done at constant pressure

W=-nRTlnV2V1W=-(0.10)(8.314J/mol.K脳500K200脳10-6m3ln(1000)2000脳cm3=330J

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