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The probability density for finding a particle at position x is P1x2 = • a 11 - x2 -1 mm … x 6 0 mm b11 - x2 0 mm … x … 1 mm and zero elsewhere. a. You will learn in Chapter 40 that the wave function must be a continuous function. Assuming that to be the case, what can you conclude about the relationship between a and b? b. Determine values for a and b. c. Draw a graph of the probability density over the interval -2 mm … x … 2 mm. d. What is the probability that the particle will be found to the left of the origin?

Short Answer

Expert verified

The wave function of a particle confined betweenx=-4mmandx=4mm

Step by step solution

01

(a)The wave function of a particle confirmed  between x=-4mm and x=4mm is shown in the figure below

02

Using the concept of similar triangles, we have

cψx=4xψx=c4x∫-∞+∞ψx2dx=1∫-4+4ψx2dx=1∫-40ψx2dx+∫04ψx2dx=1

The statement particle has to land somewhere on the x-axis is expressed mathematically as

03

Now in the case

∫-40C4x2dx+∫04C4x2dx=1C216∫-40x2dx+∫04C216x2dx=1C216x33-40+C216x3304=1C216643+C216644=1=14C23+4C23=18C2

04

(b)The probability density curve ψx2 of the particle is shown in figure below

05

(c)

06

(d)The probability of finding the particle in the interval -2.0mm ≤x≤2.0mm is

P(-2.0mm≤x≤2.0mm)=∫-22ψx2dx=∫-22C4x2dx=C216∫-22x2dx=3128x33-22=3128163=18=0.125

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