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Short Answer

Expert verified

So the length of the pulse will be 85m

Step by step solution

01

Given information

Sound waves of 498 Hz and 502 Hz are superimposed at a temperature where the speed of sound in air is 340 m/s. What is the length ∆x of one wave packet?

02

Step:2 Calculation

Here Δf=502-498=4Hz

SoΔt=14=0.35s.

SoΔx=0.25×340=85m.

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