/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 11 One physics professor talking pr... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

One physics professor talking produces a sound intensity level of 52 dB. It’s a frightening idea, but what would be the sound intensity level of 100 physics professors talking simultaneously?

Short Answer

Expert verified

The intensity level of 100 professors talking simultaneously is 70dB

Step by step solution

01

Step 1. Write the given information.

A professor is talking

The intensity of the sound is β= 52dB

100 professors talk simultaneously.

02

Step 2. To determine the intensity of sound produced by 100 professors

The intensity of the sound is given by

I=Io×10β/10dB

Here, Io is the threshold hearing of humans. The average value is 1X10-12 W/m2.

Substitute the known values in the above expression

localid="1649072838046" I=(1×10-12)×1052dB/10dBI=1.5×10-7W/m2

When 100 professors talk simultaneously, the intensity of the sound would become
I=100×1.5×10-7W/m2I=1.5×10-5W/m2

The intensity level is given by
β=10dBlog10IIo
substitute the known values
β=10dBlog101.5×10-51×10-12β=70dB

Therefore, the intensity level produced by 100 professors is 70 dB

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A distant star system is discovered in which a planet with

twice the radius of the earth and rotating 3.0 times as fast as the

earth orbits a star with a total power output of 6.8×1029W.

a. If the star’s radius is 6.0 times that of the sun, what is the

electromagnetic wave intensity at the surface? Astronomers

call this the surface flux. Astronomical data are provided

inside the back cover of the book.

b. Every planet-day (one rotation), the planet receives9.4×1022J.

of energy. What is the planet’s distance from its star? Give

your answer in astronomical units (AU), where 1 AU is the

distance of the earth from the sun.

Earthquakes are essentially sound waves—called seismic

waves—traveling through the earth. Because the earth is solid, it can support both longitudinal and transverse seismic waves. The speed of longitudinal waves, called P waves, is 8000 m/s. Transverse waves, called S waves, travel at a slower 4500 m/s. A seismograph records the two waves from a distant earthquake. If the S wave arrives 2.0 min after the P wave, how far away was the earthquake? You can assume that the waves travel in straight lines, although actual seismic waves follow more complex routes.

A wave pulse travels along a stretched string at a speed of 200 cm/s. What will be the speed if:

a. The string’s tension is doubled?

b. The string’s mass is quadrupled (but its length is unchanged)?

c. The string’s length is quadrupled (but its mass is unchanged)?

Note: Each part is independent and refers to changes made to the original string

A loudspeaker on a pole is radiating 100 W of sound energy in all directions. You are walking directly toward the speaker at 0.80 m/s. When you are 20 m away, what are (a) the sound intensity level and (b) the rate (dB/s) at which the sound intensity level is increasing? Hint: Use the chain rule and the relationship log10 x = ln x/ln 10.

The string in FIGURE P16.60 has linear density μ. Find an expression in terms of M, μ, and θfor the speed of waves on the string.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.