/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 9 Although the evidence is weak, t... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 29: Q. 9 (page 830)

Although the evidence is weak, there has been concern in recent years over possible health effects from the magnetic fields generated by electric transmission lines. A typical high-voltage transmission line is 20mabove the ground and carries a 200Acurrent at a potential of 110kV.

a. What is the magnetic field strength on the ground directly under such a transmission line?

b. What percentage is this of the earth鈥檚 magnetic field of 50渭罢?

Short Answer

Expert verified

(a) The magnetic field strength is 2渭罢.

(b) Percentage will be4%.

Step by step solution

01

Part (a) Step 1: Given information

We have given,

Height of transmission line =20m

Current ion transmission line =200A

we have to find the magnetic field at the ground due to transmission line.

02

Simplify

The magnetic field strength due to long wire is

B=渭0I2蟺搁=4蟺脳10-7脳2002蟺脳20B=2脳10-6T

03

Part (b) Step 1: Given information

We have given,

Magnetic field of the earth = 50脳10-6T

we have to find the percentage of transmission magnetic strength to earth magnetic strength.

04

Simply

The percentage will be

percentage=magneticfieldofwiremagneticfieldofearth脳100%percentage=25脳100%percentage=4%

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

a. In FIGURE P29.76, a long, straight, current-carrying wire of linear mass density 渭is suspended by threads. A magnetic field perpendicular to the wire exerts a horizontal force that deflects the wire to an equilibrium angle 胃. Find an expression for the strength and direction of the magnetic field B鈬赌.

b. What B鈬赌deflects a 55 g/m wire to a 12掳 angle when the current is 10 A?

What is the magnetic field at the position of the dot in FIGURE. Give your answer as a vector.

The 10-turn loop of wire shown in FIGURE P29.71 lies in a horizontal plane, parallel to a uniform horizontal magnetic field, and carries a 2.0 A current. The loop is free to rotate about a nonmagnetic axle through the center. A 50 g mass hangs from one edge of the loop. What magnetic field strength will prevent the loop from rotating about the axle?

The coaxial cable shown in figureP29.56consists of a solid inner conductor of radius R1surrounded by a hollow, very thin outer conductor of radius R2. The two carry equal currents I, but in opposite directions. The current density is uniformly distributed over each conductor.

a. Find expressions for three magnetic fields: within the inner conductor, in the space between the conductors, and outside the outer conductor.

The element niobium, which is a metal, is a superconductor (i.e., no electrical resistance) at temperatures below 9K. However, the superconductivity is destroyed if the magnetic field at the surface of the metal reaches or exceeds 0.10T. What is the maximum current in a straight,3mm diameter superconducting niobium wire?
See all solutions

Recommended explanations on Physics Textbooks

Engineering Physics

Read Explanation

Linear Momentum

Read Explanation

Waves Physics

Read Explanation

Energy Physics

Read Explanation

Nuclear Physics

Read Explanation

Electromagnetism

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.