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Chapter 37: Q. 32 (page 1083)

The fission process n+U235鈫�U236鈫�Ba144+Kr89+3n converts 0.185u of mass into the kinetic energy of the fission products. What is the total kinetic energy in MeV ?

Short Answer

Expert verified

We find the kinetic energy to be equal to, Ek=167MeV

Step by step solution

01

Given Information

The fission process n+U235鈫�U236鈫�Ba144+Kr89+3nconverts 0.185uof mass into the kinetic energy of the fission products.

02

Calculation

Here the mass is getting converted to kinetic energy hence the kinetic energy will be equal to
Ek=螖mc2=0.185脳1.6脳10-27脳3脳1082=2.66脳10-11J=1.67脳10-8eV=167MeV

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