/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 58 A 2.0-mm-diameter glass sphere h... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 23: Q. 58 (page 656)

A 2.0-mm-diameter glass sphere has a charge of +1.0nC. What speed does an electron need to orbit the sphere 1.0mm above the surface?

Short Answer

Expert verified

The electron needs to orbit the sphere at a speed of 3.97x107m/s

Step by step solution

01

Given information and formula 

Given :

Diameter of glass sphere : 2.0-mm

Charge on glass sphere : +1.0nC

Distance of the sphere from the surface :1.0mm

Theory used :

Electrostatic force on a sphere concentric on the center generates the electron centripetal force. That is :

Fe=Fc

02

Calculating the orbital speed

Electrostatic force on a sphere concentric on the center generates the electron centripetal force.

Fe=Fc鈬�14蟺蔚0脳Qer2=mv虏r鈬�9脳109脳10-9脳1.6脳10-1910-3=9.11脳10-31v虏鈬�v2=1.44x10-159.11x10-31鈬�v=1.15068x10-47=3.97x107m/s

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You鈥檝e been assigned the task of determining the magnitude and direction of the electric field at a point in space. Give a step-by-step procedure of how you will do so. List any objects you will use, any measurements you will make, and any calculations you will need to perform. Make sure that your measurements do not disturb the charges that are creating the field.

Rank in order, from largest to smallest, the electric field strengths E1 to E5 at the five points inFIGURE Q23.11. Explain.

An electric dipole is formed from two charges, 卤q, spaced1.0cm apart. The dipole is at the origin, oriented along the y-axis. The electric field strength at the point x,y=(0cm,10cm)is 360N/C.

a. What is the charge q? Give your answer in nC.

b. What is the electric field strength at the pointx,y=10cm,0cm?

The irregularly shaped area of charge in FIGURE Q23.7 has surface charge density畏i. Each dimension (x and y) of the area is reduced by a factor of 3.163.

a. What is the ratio 畏f/畏i , where 畏fis the final surface charge density?

b. An electron is very far from the area. What is the ratioFf/Fi of the electric force on the electron after the area is reduced to the force before the area was reduced?

An ammonia moleculeNH3 has a permanent electric dipole moment5.0脳1030Cm. A proton is 2.0nm from the molecule in the plane that bisects the dipole. What is the electric force of the molecule on the proton?
See all solutions

Recommended explanations on Physics Textbooks

Scientific Method Physics

Read Explanation

Oscillations

Read Explanation

Magnetism and Electromagnetic Induction

Read Explanation

Thermodynamics

Read Explanation

Work Energy and Power

Read Explanation

Wave Optics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.