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An electric dipole is formed from two charges, ±q, spaced1.0cm apart. The dipole is at the origin, oriented along the y-axis. The electric field strength at the point x,y=(0cm,10cm)is 360N/C.

a. What is the charge q? Give your answer in nC.

b. What is the electric field strength at the pointx,y=10cm,0cm?

Short Answer

Expert verified

(a) The charge q is 2.003×10-11C.

(b) The electric field strength is8.96N/C

Step by step solution

01

Given information (part a)

Coordinates

+q=0,0.5cm-q=0,0.5cmE=360N/C

02

Explanation (part a)

The electric field due to a dipole is given by

E=p/2πεy3Where P=dipole moment and r= distance of dipole to point of electric field=10cm=0.10m. E=electric field strength at (0,10)=360N/C.

So, role="math" localid="1648660696169" E=p/2πεr3

role="math" localid="1648660707891" p=2πεr3E=2π×8.854×10-12×(0.10m)3×360N/C=2.003×10-13Cm

q=ÒÏd=2.003×10-13Cm0.01m=2.003×10-11C

03

Given information (part b)

+q=0,0.5cm-q=0,0.5cmE=360N/C

04

Explanation (part b)

The electric field at the perpendicular axis 10,0:

E=q×xπϵ0d2+4x23=2.003×10-11C×0.10mπ×8.854×10-120.012+4×(0.1)23=8.96N/C

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Most popular questions from this chapter

FIGURE is a cross section of two infinite lines of charge that extend out of the page. The linear charge densities are ±λ. Find an expression for the electric field strength Eat height yabove the midpoint between the lines.

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Hint: This exercise requires an integration. Think about how to handle the absolute value sign.

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