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Chapter 23: Q. 15 (page 654)

Two10cmdiameter charged rings face each other,20cmapart. Both rings are charged to+20nC. What is the electric field strength at (a) the midpoint between the two rings and (b) the center of the left ring?

Short Answer

Expert verified

a.Electric field at midpoint between the two rings is0N/C.

b. Electric field at the center of the left ring is4.108脳103N/C.

Step by step solution

01

Calculation for Electric field at midpoint between the two rings (part a)

(a)

Diameter of both circle is10cm.

Radius is 5cm.

Charge on both circle is+20nC.

Distance between both circle is20cm.

Formula used:

Electric field due to a ring of radiusRand chargeQat a distanceris given by,

E=kQrr2+R23/2.......(1)

Electric field at the center of both rings will be0N/C.

Because electric field due to both rings will be equal and in opposite direction.

02

Figure for given situation

03

Calculation of electric field at the center of the left ring  (part b)

(b)

Electric field due left circle at its own center is0N/C.

This can find out by substituting0forrin equation(1).

The electric field generated by the right ring in the middle of the left circle is now in the left direction, and its magnitude may be measured using equation(1).

E=9脳109N路m2/C220脳10-9C20脳10-2m(0.2m)2+(0.05m)23/2

E=4.108脳103N/C

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