/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 55 A positron is an elementary part... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 23: Q. 55 (page 656)

A positron is an elementary particle identical to an electron except that its charge is +e. An electron and a positron can rotate about their center of mass as if they were a dumbbell connected by a massless rod. What is the orbital frequency for an electron and a positron1.0nm apart?

Short Answer

Expert verified

The orbital frequency for the electron and positron is1.125脳105Hz

Step by step solution

01

Given information and formula used

Given :

Distance between the electron and positron : 1.0nm

Theory used :

The centripetal force is generated by electrostatic force. That is,

Fe=Fc鈬�14蟺蔚0脳e2d2=mw虏d2
02

Evaluating the required orbital frequency 

The positron has the same mass as the electron, and the distance between them is d=1x10-9.

The mass is equal, and the center of mass is at role="math" localid="1649128476171" d2=0.5x10-9

The centripetal force is generated by electrostatic force. So

Fe=Fc鈬�14蟺蔚0脳e2d2=mw虏d2鈬�w2=9脳10-9脳(1.6x10-19)2脳2(9.11脳10-31)(1x10-9)3鈬�w=7x105rad/s

We now have orbital frequency :

f=w2蟺=7x1052脳3.14=1.125x105Hz

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The combustion of fossil fuels produces micron-sized particles of soot, one of the major components of air pollution. The terminal speeds of these particles are extremely small, so they remain suspended in air for very long periods of time. Furthermore, very small particles almost always acquire small amounts of charge from cosmic rays and various atmospheric effects, so their motion is influenced not only by gravity but also by the earth's weak electric field. Consider a small spherical particle of radius r, density 蚁, and charge q. A small sphere moving with speed v experiences a drag force Fdrag=6蟺畏rv, where 畏 is the viscosity of the air. (This differs from the drag force you learned in Chapter 6 because there we considered macroscopic rather than microscopic objects.)

a. A particle falling at its terminal speed vtermis in equilibrium with no net force. Write Newton's first law for this particle falling in the presence of a downward electric field of strength E, then solve to find an expression for vterm.

b. Soot is primarily carbon, and carbon in the form of graphite has a density of 2200kg/m3. In the absence of an electric field, what is the terminal speed in mm/s of a 1.0-渭m-diameter graphite particle? The viscosity of air at 20掳C is 1.8脳10-5kg/ms.

c. The earth's electric field is typically (150 N/C , downward). In this field, what is the terminal speed in mm/s of a 1.0 渭m-diameter graphite particle that has acquired 250 extra electrons?

FIGUREP23.38shows three charges at the corners of a square. Write the electric field at point Pin component form.

Reproduce FIGURE Q23.2on your paper. For each part, draw a dot or dots on the figure to show any position or positions (other than infinity) where 鈫�E=鈫�0.

An electron in a vacuum chamber is fired with a speed of 8300km/stoward a large, uniformly charged plate 75cm away. The electron reaches a closest distance of 15cm before being repelled. What is the plate鈥檚 surface charge density?

A sphere of radius R has charge Q. The electric field strength at distancer>RisEi. What is the ratio Ef/Eiof the final to initial electric field strengths if

(a) Q is halved,

(b) R is halved, and

(c) r is halved (but is still>R)? Each part changes only one quantity; the other quantities have their initial values
See all solutions

Recommended explanations on Physics Textbooks

Circular Motion and Gravitation

Read Explanation

Magnetism and Electromagnetic Induction

Read Explanation

Mechanics and Materials

Read Explanation

Measurements

Read Explanation

Medical Physics

Read Explanation

Kinematics Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.